<span>We have log (3) x = 9. After that Paul wrote: 3 ^x = 9. 3^x = 3^2, x = 2 ( but this is wrong in his firs line ). If we have log˙(x) a = b then: a = x^b, but Paul wrote it in a form: b = x^a. On the other hand, Scott was right. He wrote: 3^9 = x and as a result he had: x = 19,683. Answer: Paul is wrong. Hope I helped! :) Cheers!</span>
For this case we must find the percentage of error in the estimation of the pace of Charlie's dog. For this, we subtract the approximate weight minus the actual weight:
This represents the variation of the weight
To find the error, we divide the variation between the real weight and multiply it by 100:
Rounding to the nearest tenth:
Answer:
error=5.5%
If they lose 5 yards on each of the three plays, that would be -15. 35 - 15 will give you 20 (unless they are on the opposite side, which then will give you 50 yards).
Dang, those must've been horrible plays.