Answer:
<em><u>263.76</u></em><em><u> </u></em><em><u>in</u></em><em><u>^</u></em><em><u>3</u></em>
VOLUME OF FIGURE=VOL.OF CONE+VOL.OF CYLINDER +VOL.OF HEMISPHERE
=(1/3×3.14×3×3×4)+(3.14×3×3×6)+(2/3×3.14×3×3×3)
=37.68+169.56+56.52
=263.76in^3
Answer:
x = 8 base angle = 81 degrees
Step-by-step explanation:
Answer:
a) The area of the triangle AQB is 43 square centimeters.
b) The length of the line segment AQ is approximately 14.866 centimeters.
Step-by-step explanation:
a) The procedure consist in subtracting the areas of triangles APQ, ASB and BRQ of the area the rectangle, that is to say:
![A = (9\,cm)\cdot (14\,cm) - \frac{1}{2}\cdot (5\,cm)\cdot (14\,cm) - \frac{1}{2}\cdot (8\,cm)\cdot (9\,cm) -\frac{1}{2}\cdot (4\,cm) \cdot (6\,cm)](https://tex.z-dn.net/?f=A%20%3D%20%289%5C%2Ccm%29%5Ccdot%20%2814%5C%2Ccm%29%20-%20%5Cfrac%7B1%7D%7B2%7D%5Ccdot%20%285%5C%2Ccm%29%5Ccdot%20%2814%5C%2Ccm%29%20-%20%5Cfrac%7B1%7D%7B2%7D%5Ccdot%20%288%5C%2Ccm%29%5Ccdot%20%289%5C%2Ccm%29%20-%5Cfrac%7B1%7D%7B2%7D%5Ccdot%20%284%5C%2Ccm%29%20%5Ccdot%20%286%5C%2Ccm%29)
![A = 43\,cm^{2}](https://tex.z-dn.net/?f=A%20%3D%2043%5C%2Ccm%5E%7B2%7D)
The area of the triangle AQB is 43 square centimeters.
b) The length of the line segment AQ is determined by Pythagorean Theorem:
(1)
![AQ = \sqrt{(5\,cm)^{2}+(14\,cm)^{2}}](https://tex.z-dn.net/?f=AQ%20%3D%20%5Csqrt%7B%285%5C%2Ccm%29%5E%7B2%7D%2B%2814%5C%2Ccm%29%5E%7B2%7D%7D)
![AQ \approx 14.866\,cm](https://tex.z-dn.net/?f=AQ%20%5Capprox%2014.866%5C%2Ccm)
The length of the line segment AQ is approximately 14.866 centimeters.
<h2><em>Hmm</em><em> </em><em>my</em><em> </em><em>answer</em><em> </em><em>is</em><em> </em><em>A</em><em>.</em><em> </em><em> </em></h2><h2><em>Because</em><em> </em><em>I</em><em> </em><em>calculated</em><em> </em><em>it</em><em> </em></h2><h2><em>Hope</em><em> </em><em>it helps</em><em> </em><em>#brainliestbunch</em><em> </em></h2>