If A(t) is the amount of salt in the tank at time t, then A(0) = 50 g and
A'(t) = (1 g/L)*(3 L/min) - (A(t)/120 g/L)*(3 L/min)
Multiply both sides by , so that the left side can be condensed as the derivative of a product:
Integrate both sides and solve for A(t).
Given that A(0) = 50 g, we have
so that the amount of salt in the tank at time t is
Answer:
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Step-by-step explanation:
To find the total amount of something, when given the percent and how much value the percent is, use this
This way we get:
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Answer:
The value of the house after adding the garage is $135,700.
Step-by-step explanation:
Given,
value of house before adding garage = $118,200.00
we need to find the value of house after adding two car garage.
Solution,
Since after adding two car garage the value of the house increased by 15%.
So firstly we will find out the 15% of the value of the house after adding garage.
So we can say that;
15% of the value of the house after adding garage is equal to 15 divided by 100 the multiplied with the value of the house before adding garage.
15% of the value of the house after adding garage =
Now, The value of the house after adding garage is equal to the sum of value of house before adding garage and 15% of value of house before adding garage.
We can frame it in equation form as;
The value of the house after adding garage =
Hence The value of the house after adding the garage is $135,700.