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sveticcg [70]
3 years ago
8

A patio deck in the shape of a parallelogram has three square cutouts for trees to grown through. Each square has a side length

of 4 1/2 feet. What area of wood boards is needed to cover the deck while leaving room for the square cutouts?

Mathematics
1 answer:
luda_lava [24]3 years ago
7 0

The area of the deck is 50.4 x 22 = 1108.8 square ft.

The area of 1 cut out is 4.5 x 4.5 = 20.25

There are 3 cut outs so total area of the cut outs is 20.25 x 3 = 60.75 square ft.

The total area of the boards is : 1108.8 - 60.75 = 1048.05 square feet.

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Elan Coil [88]

Answer: d = 1

Step-by-step explanation:

First distribute the 7 to each term of (6 + d) = 42 + 7d = 49 now subtract 42 from both sides which = 7d = 7. Divide by 7 = 7d/7 = 7/7 = d = 1

3 0
3 years ago
Find the quadratic function y=a(x-h)^2 whose graph passes through the given points. (12,-7) and (9,0)
ryzh [129]

Answer:

y = (-7/3)(x - 9)

Step-by-step explanation:

<em><u>(12, - 7)</u></em>

y = a(x - h)^2

-7 = a(12 - h)^2

- 7 = a(144 - 24x + h^2)

<em><u>(9,0)</u></em>

0 = a(x - h)^2

0 = a(9 - h)^2

0 = a(81 - 18h + h^2)

From (9,0) we can conclude that

a = 0

or

(9 - h)^2 = 0

Let's try the second possibility.

Take the square root of both sides.

9 - h = sqrt(0)

Add h to both sides

9 - h = 0  

h = 9

So now what we have is

y = a(x - 9)

Use the first equation to get a

-7 = a(12 - 9)

-7 = a(3)

-7/3 = a

Answer

y = (-7/3)(x - 9)

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Well how many markers does she have

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