Ask question

Ask question

All categories

3 years ago

10

A machine in a laboratory is set to steadily increase the temperature inside. The temperature in degrees Celsius inside the mach

ine after being turned on is a function of time, in seconds, given by the equation f(t)=22+1.3t
1. What does f(3) mean in this situation?
2. Find the value of f(3) and interpret the value.
3. What does the equation f(t)=35 mean in this situation?
4. Solve the equation to find the value of t for the question.

2 answers:

vaieri [72.5K]3 years ago

6 0

Answer:

1) f(3) means the temperature after 3 seconds

2) f(3) = 22 + 1.3(3) = 25.9

Temperature after 3 seconds is 25.9°C

3) f(t) = 35 means after t seconds, temperature was 35°C

4) 35 = 22 + 1.3t

1.3t = 13

t = 10 seconds

Semenov [28]3 years ago

5 0

Step-by-step explanation:

<u>Step 1: Answer the first question</u>

f(3) means the temperature after 3 seconds

<u>Step 2: Answer the second question</u>

The value of $f(3) = 22 + 1.3(3)$ → 25.9 degrees

The value of f(3) which is 25.9 means that after 3 seconds, the temperature is 25.9 degrees.

<u>Step 3: Answer the third question</u>

f(t) = 35 means that after a t amount of seconds, the temperature is 35 degrees.

<u>Step 4: Answer the fourth question</u>

$f(t) = 35$ so... $35 = 22 + 1.3t$

$35 - 22 = 22 - 22 + 1.3t$

$13 = 1.3t$

$13 / 1.3 = 1.3t / 1.3$

$10 = t$

10 seconds

You might be interested in

Please assist me with this problem

n200080 [17]

Answer:

The answer to your question is 90 dB

Step-by-step explanation:

Data

I = 10⁻³

I⁰ = 10⁻¹²

Formula

Loudness = 10log ( $\frac{I}{Io}$ )

Process

1.- To solve this problem, just substitute the values in the equation and do the operations.

2.- Substitution

Loudness = 10 log $(\frac{10^{-3}}{10^{-12}} )$

3.- Simplify

Loudness = 10log (1 x 10⁹)

Loudness = 10(9)

Loudness = 90

7 0

3 years ago

Please help NO LINKS

ankoles [38]

54 shots. 9 out of 12 means she is making 75% of her shots. 75% of 72 is 54.

4 0

3 years ago

Help me with this question <br> Please I need help

34kurt

Answer:

384 cm²

Step-by-step explanation:

The shape of the figure given in the question above is simply a combined shape of parallelogram and rectangle.

To obtain the area of the figure, we shall determine the area of the parallelogram and rectangle. This can be obtained as follow:

For parallelogram:

Height (H) = 7.5 cm

Base (B) = 24 cm

Area of parallelogram (A₁) =?

A₁ = B × H

A₁ = 24 × 7.5

A₁ = 180 cm²

For rectangle:

Length (L) = 24 cm

Width (W) = 8.5 cm

Area of rectangle (A₂) =?

A₂ = L × W

A₂ = 24 × 8.5

A₂ = 204 cm²

Finally, we shall determine the area of the shape.

Area of parallelogram (A₁) = 180 cm²

Area of rectangle (A₂) = 204 cm²

Area of figure (A)

A = A₁ + A₂

A = 180 + 204

A = 384 cm²

Therefore, the area of the figure is 384 cm²

3 0

3 years ago

A line segment has endpoints C(11,-2) and D(13,10) determine the midpoint of this line segment

IRINA_888 [86]

Step-by-step explanation:

Use midpoint formula ,

x = 12 , y = 4

midpoint of line segment is (12,4)

8 0

3 years ago

mr.browns salary is 32,000 and imcreases by $300 each year, write a sequence showing the salary for the first five years when wi

chubhunter [2.5K]

Hello!

We have the following data:

a1 (first term or first year salary) = 32000

r (ratio or annual increase) = 300

n (number of terms or each year worked)

We apply the data in the Formula of the General Term of an Arithmetic Progression, to find in sequence the salary increases until it exceeds 34700, let us see:

formula:

$a_n = a_1 + (n-1)*r$

* second year salary

$a_2 = a_1 + (2-1)*300$

$a_2 = 32000 + 1*300$

$a_2 = 32000 + 300$

$\boxed{a_2 = 32300}$

* third year salary

$a_3 = a_1 + (3-1)*300$

$a_3 = 32000 + 2*300$

$a_3 = 32000 + 600$

$\boxed{a_3 = 32600}$

* fourth year salary

$a_4 = a_1 + (4-1)*300$

$a_4 = 32000 + 3*300$

$a_4 = 32000 + 900$

$\boxed{a_4 = 32900}$

* fifth year salary

$a_5 = a_1 + (5-1)*300$

$a_5 = 32000 + 4*300$

$a_5 = 32000 + 1200$

$\boxed{a_5 = 33200}$

We note that after the first five years, Mr. Browns' salary has not yet surpassed 34700, let's see when he will exceed the value:

* sixth year salary

$a_6 = a_1 + (6-1)*300$

$a_6 = 32000 + 5*300$

$a_6 = 32000 + 1500$

$\boxed{a_6 = 33500}$

* seventh year salary

$a_7 = a_1 + (7-1)*300$

$a_7 = 32000 + 6*300$

$a_7 = 32000 + 1800$

$\boxed{a_7 = 33800}$

* eighth year salary

$a_8 = a_1 + (8-1)*300$

$a_8 = 32000 + 7*300$

$a_8 = 32000 + 2100$

$\boxed{a_8 = 34100}$

* ninth year salary

$a_9 = a_1 + (9-1)*300$

$a_9 = 32000 + 8*300$

$a_9 = 32000 + 2400$

$\boxed{a_9 = 34400}$

* tenth year salary

$a_{10} = a_1 + (10-1)*300$

$a_{10} = 32000 + 9*300$

$a_{10} = 32000 + 2700$

$\boxed{a_{10} = 34700}$

we note that in the tenth year of salary the value equals but has not yet exceeded the stipulated value, only in the eleventh year will such value be surpassed, let us see:

* eleventh year salary

$a_{11} = a_1 + (11-1)*300$

$a_{11} = 32000 + 10*300$

$a_{11} = 32000 + 3000$

$\boxed{\boxed{a_{11} = 35000}}\end{array}}\qquad\checkmark$

Respuesta:

In the eleventh year of salary he will earn more than 34700, in the case, this value will be 35000

________________________

¡Espero haberte ayudado, saludos... DexteR! =)

7 0

3 years ago