(792 bulbs) To answer this question one would multiply the number of rows times the number of bulbs 6 x132= ? to get the answer.
Answer:
3÷1/2 and 1/2÷3 there is no difference bc they both add up the same as each other
Essentially what you're given is the following
![[total gallons for the specified time] = [gallons]*[days]\\](https://tex.z-dn.net/?f=%5Btotal%20gallons%20for%20the%20specified%20time%5D%20%3D%20%5Bgallons%5D%2A%5Bdays%5D%5C%5C)
The easiest way to approach this problem is to use the given information to find the amount of milk the family consumes over the course of a day.

So now that we know that the family drinks
gallons of milk each day, we can multiply by the desired amount of days to discover how much milk the family drinks over that period of time.

So from this, we now know that the family drinks
gallons of milk over the course of 4 days.
First you would add 2z to both sides
6k = 12 + 2z
second divide 6 from both sides
K = (12 + 2z) / 6
^^ thats your answer :)
AFC and DFB any pair that are across from each other