Question

The molar heat of fusion of platinum (Pt) is 4.700 kcal/mol. How much heat must be added to 85.5 g of

Answer 1

Answer:

2.06 kcal

Explanation:

Answer 2

Answer:

2.07 Kcal heat must be added to completely melt the platinum.

Explanation:

Given data:

Molar heat of fusion =  4.700 Kcal / mol

Mass of platinum = 85.5 g

Heat of fusion = ?

Solution:

Formula:

ΔH = n × molar heat of fusion

n = number of moles

Now we will calculate the number of moles:

Number of moles = mass / molar mass

Number of moles = 85.5 g /195.08 g/mol

Number of moles = 0.44 mole

ΔH = n × molar heat of fusion

ΔH = 0.44 mol × 4.700 Kcal / mol

ΔH = 2.07 Kcal