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3 years ago

Which statement describes an intensive property of matter?

Chemistry

2 answers:

loris [4]3 years ago

7 0

The correct option is A.

Matters generally has two types of properties, these are intensive and extensive properties. An intensive property of a substance refers to that property that does not depend on the size or the quantity of that substance that is available. Another name for intensive properties is physical properties. These properties remain the same all the time no matter the quantity of the substance present. One example of intensive property is the density of water. No matter the quantity of water present or the location where you take the water sample from, the density of water will always be the same, that is, it is the same for every sample of water. Extensive properties on the other hand depend on the amount of that substance that is present. Examples are mass, weight, length and volume.

andrey2020 [161]3 years ago

6 0

Among the choices above, I think the statement that best describes an intensive property of matter is letter B which is " It depends on how a substance was formed." Intensive properties are those property which does not depend upon the amount of substance present in the system. Such as refractive-index, density etc

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Juli2301 [7.4K]

Answer:

$\large \boxed{\text{44.5 mL}}$

Explanation:

When adding or subtracting values, you must round your answer to the same "place" as the measurement with its last significant figure furthest to the left.

That is, you round off to the same number of decimal places as the measurement with the fewest decimal places.

$\begin{array}{r|r}19.9& \text{3 mL}\\14.0&\text{mL}\\10.6&\text{mL} \\\mathbf{44.5} &\textbf{3 mL}\\\end{array}$

The measurements of 14.0 and 10.6 have one digit after the decimal point, so you round the sum to have only one digit to the right of the decimal.

The number to be dropped (3) is less than 5, so you drop it.

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3 years ago

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3 years ago

An analytical chemist weighs out 0.093g of an unknown monoprotic acid into a 250mL volumetric flask and dilutes to the mark with

Kamila [148]

Answer:

The molar mass of the unknown acid is 89 g/mol

Explanation:

Step 1: The balanced equation

HA(aq) + NaOH(aq) → NaA(aq) + H2O(l)

It takes 1 mole of NaOH to neutralize 1 mole of the triprotic acid. This is called the reaction stoichiometry.

Step 2: Data given

Mass of the acid = 0.093 grams

volume = 250 mL

titrates with 0.16 M NaOH

adds 6.5 mL NaOH

Step 3: Calculate moles of NaOH

We know the concentration and volume of NaOH needed to neutralize the acid.

By determining the moles of NaOH in that volume in liters (95.9mL=0.0959L), the moles of acid in the original sample can be determined from the reaction stoichiometry.

Moles = Molarity * Volume

Moles = 0.16 M * 0.0065 L

Moles = 0.00104 moles NaOH

Step 4: Calculate moles of the unknown acid:

It takes 1 mole of NaOH to neutralize 1 mole of the triprotic acid. This is called the reaction stoichiometry.

For 0.00104 moles NaOH we have 0.00104 moles of HA

Step 5: Calculate the molar mass of the acid

Molar mass Ha = Mass Ha / moles Ha

Molar mass Ha = 0.093 grams / 0.00104 moles

Molar mass Ha = 89.42 g/mol ≈89 g/mol

The molar mass of the unknown acid is 89 g/mol

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antiseptic1488 [7]

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