At equivalence there is no more HA and no more NaOH, for this particular reaction. So that means we have a beaker of NaA and H2O. The H2O contributes 1 x 10-7 M hydrogen ion and hydroxide ion. But NaA is completely soluble because group 1 ion compounds are always soluble. So NaA breaks apart in water and it just so happens to be in water. So now NaA is broken up. The Na+ doesn't change the pH but the A- does change the pH. Remember that the A anion is from a weak acid. That means it will easily attract a hydrogen ion if one is available. What do you know? The A anion is in a beaker of H+ ions! So the A- will attract H+ and become HA. When this happens, it leaves OH-, creating a basic solution, as shown below.
I’m in chemistry too. Giving this my best guess I’d say
Independent: Gem Mines
Dependent: Gem clarity
Controlled: Temperature
<h2>Hello!</h2>
The answer is:
The new volume is equal to 206.5 L.
<h2>Why?</h2>
To solve this problem, we need to assume that the pressure is constant, and use the Charle's Law equation, so, solving we have:
We are given:
Then, using the Charle's Law equation, we have:
Hence, we have that the new volume is equal to 206.5 L.
Have a nice day!
