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2 years ago

Work out the co ordinates of the midpoint of (-2,-1) and (-2,4)

Mathematics

2 answers:

aliya0001 [1]2 years ago

7 0

Answer:

(-2, 1.5)

Step-by-step explanation:

Midpoint:

(-2 + -2)/2, (-1 + 4)/2

(-4)/2, 3/2

-2, 1.5

s2008m [1.1K]2 years ago

4 0

Answer:

$(-2,\frac{3}{2})$

Step-by-step explanation:

To find the midpoint, simply use the Midpoint Formula.

The Midpoint Formula states that for two points $(x_1,y_1)$ and $(x_2,y_2)$ , the midpoint will be: $(\frac{x_1+x_2}{2} ,\frac{y_1+y_2}{2} )$ .

So, here, $(x_1,y_1)$ = (-2, -1) and $(x_2,y_2)$ = (-2, 4). The midpoint is then: $(\frac{-2+(-2)}{2} ,\frac{-1+4}{2} )=(\frac{-4}{2} ,\frac{3}{2} )=(-2,\frac{3}{2})$

Thus, the answer is $(-2,\frac{3}{2})$ .

Hope this helps!

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700+a=3944-b=c-80=3000

velikii [3]

Answer:

A = 3244

B = 864

C = 3080

Step-by-step explanation:

700 + a = 3944

-700 -700

a = 3244

3944 - b = c - 80 = 3000

c - 80 = 3000

+80 +80

c = 3080

3944 - b = c ---> 3944 - b = 3080

-3944 -3944

-b = -864 ---> $\frac{-b}{-1} = \frac{-864}{-1}$

7 0

3 years ago

Jonah read a total of 24 books over 3 months. If Jonah has read 32 books so far, how many months has he been with his book club?

lilavasa [31]

O think the solution is 33 because if u add u get 33

6 0

2 years ago

Rework problem 35 from the Chapter 2 review exercises in your text, involving auditioning for a play. For this problem, assume 9

sweet-ann [11.9K]

Answer: 1) 6300 ways

2) 2520 ways

3) 0.067

Step-by-step explanation:

For this problem, assume 9 males audition, one of them being Winston, 5 females audition, one of them being Julia, and 6 children audition. The casting director has 3 male roles available, 1 female role available, and 2 child roles available.

How many different ways can these roles be filled from these auditioners?

Available: 9M and 5F and 6C

Cast: 3M and 1F and 2C

As it is not ordered: C₉,₃ * C₅,₁ * C₆,₂

C₉,₃ = 9!/3!.6! = 84

C₅,₁ = 5!/1!.4! = 5

C₆,₂ = 6!/2!.4! = 15

C₉,₃ * C₅,₁ * C₆,₂ = 84.5.15 = 6300

How many different ways can these roles be filled if exactly one of Winston and Julia gets a part?

2 options Winston gets or Julia gets it:

1) Winston gets it but Julia no:

8 male for 2 spots

4 females for 1 spot

6 children for 2 spots

C₈,₂ * C₄,₁ * C₆,₂

C₈,₂ = = 8!/2!.6! = 28

C₄,₁ = 4!/1!.3! = 4

C₆,₂ = 6!/2!.4! = 15

C₈,₂ * C₄,₁ * C₆,₂ = 28.4.15 = 1680

2) Julia gets it but Winston does not

8 male for 3 spots

1 female for 1 spot

6 children for 2 spots

C₈,₃ * C₆,₂

C₈,₃ = 8!/3!.5! = 56

C₆,₂ = 6!/2!.4! = 15

C₉,₃ * C₆,₂ = 56.15 = 840

1) or 2) = 1) + 2) = 1680 + 840 = 2520

What is the probability (if the roles are filled at random) of both Winston and Julia getting a part?

8 male for 2 spots

1 female for 1 spot

6 children for 2 spots

C₈,₂ * C₆,₂

C₈,₂ = = 8!/2!.6! = 28

C₆,₂ = 6!/2!.4! = 15

C₈,₂ * C₆,₂ = 28.15 = 420

p = 420/6300 = 0.067

6 0

3 years ago

"How much do students pay, on average, for textbooks during the first semester in college? From a random sample of 400 students

dezoksy [38]

Answer: The margin of error = 3.71, confidence interval = (354.04, 361.46) and it means that mean cost is lies within the confidence interval.

Step-by-step explanation:

Since we have given that

Sample size = 400

Mean = $357.75

Standard deviation = $37.89

At 95% confidence level, z = 1.96

We first find the margin of error.

Margin of error is given by

$z\times \dfrac{\sigma}{\sqrt{n}}\\\\=1.96\times \dfrac{37.89}{\sqrt{400}}\\\\=3.71$

95% confidence interval would be

$\bar{x}\pm \text{margin of error}\\\\=357.75\pm 3.71\\\\=(357.75-3.71,357.75+3.71)\\\\=(354.04,361.46)$

Hence, the margin of error = 3.71, confidence interval = (354.04, 361.46) and it means that mean cost is lies within the confidence interval.

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3 years ago

The doghouse shown has a floor , but no windows. Find the total surface area of the dog house, including the door.

Anna [14]

I hope this helps you

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3 years ago