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Sveta_85 [38]
3 years ago
10

Which of the following reflective symmetries apply to the rectangle below?

Mathematics
2 answers:
tino4ka555 [31]3 years ago
7 0

First answer is Yes , second one is No

valentina_108 [34]3 years ago
3 0

Answer:

Step-by-step explanation:

Using BF as the reflective points, A will become C and G will become E. It also works the other way around: C becomes A and E becomes G.

You would be helped if you could actually try it. If you put a mirror on BF and look first at A and G and then move so you can see C and E you should be convinced of the reflective property. Then turn the mirror around and look again.

These things look to be quite simple but it took many centuries before they were properly explained, and even then there were difficulties.

The second choice does not work at all. You cannot see any reflection the way you can with the first choice.

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3/4(x+5 1/2) = 5/8<br><br> Distributive Property <br><br> Brainly
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Answer:

x = - \frac{14}{3}

Step-by-step explanation:

Given

\frac{3}{4} (x + 5 \frac{1}{2} ) = \frac{5}{8}

Multiply both sides by 8 to clear the fractions

6(x + 5 \frac{1}{2} ) = 5 ← distribute parenthesis on left side

6x + 33 = 5 ( subtract 33 from both sides )

6x = - 28 ( divide both sides by 6 )

x = \frac{-28}{6} = - \frac{14}{3}

3 0
3 years ago
A line that passes through (-8,4) and has a slope of -5/4​
zhannawk [14.2K]

Answer:

y2-y1, x2-x1

Step-by-step explanation:

4-(-5)= 4-(-8)

4+5=4+8

9=12

9/12

3/4

the slope of line is 3/4

3 0
3 years ago
Give a real life example of two variables that very directly
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the amount of products a company sells directly affects the amount of money it has

7 0
3 years ago
Carry out the following division.​
kifflom [539]

Answer:

1: 8a²

2: 9a²b²c²

Step-by-step explanation:

1: 48a³ ÷ 6a

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4 0
3 years ago
Read 2 more answers
Given circle and circle with radii of 6cm and 4cm respectively.
noname [10]

Solution :

Given that :

The radius of circle A = 6 cm

The radius of circle C = 4 cm

In circle A

\angle EAF = \theta = 140^\circ

The length of arc EF = $2 \pi r \times \frac{\theta}{360^\circ}$

                                   $=2 \times 3.14 \times 6 \times \frac{140^\circ}{360^\circ}$

                                    = 14.653 cm

In circle C

\angle GCH = \theta = 140^\circ

The length of arc GH = $2 \pi r \times \frac{\theta}{360^\circ}$

                                   $=2 \times 3.14 \times 4 \times \frac{140^\circ}{360^\circ}$

                                    = 9.769 cm    

Therefore,

The length of EF is 14.653 cm

The length of GH is 9.769 cm

The length of EF is  1.5 times the length of GH

i.e.                   14.653  = 1.5 x 9.769

                       14.653 = 14.653

Hence proved.

                             

6 0
3 years ago
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