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2 years ago

What time factorizations of 2 to the 6th power times 5 to the 6 power

Mathematics

1 answer:

Annette [7]2 years ago

5 0

2 * 2 * 2 * 2 * 2 * 2 = 64
5 * 5 * 5 * 5 * 5 * 5 = 15625
64 * 15625 = 1,000,000

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.Write 803,000,000 in scientific notation.

Rina8888 [55]

Answer:

8.03*(10^8)

Step-by-step explanation:

6 0

2 years ago

A sequence is defined by the recursive formula f(n+1)=f(n)-2. If f(1)=18, what is f(5)?

N76 [4]

Answer:

$f(5)=10$

Step-by-step explanation:

A sequence is defined by the recursive formula $f(n+1)=f(n)-2$

If $f(1)=18,$ then

for $n=1: f(2)=f(1+1)=f(1)-2=18-2=16$

for $n=2: f(3)=f(2+1)=f(2)-2=16-2=14$

for $n=3: f(4)=f(3+1)=f(3)-2=14-2=12$

for $n=4: f(5)=f(4+1)=f(4)-2=12-2=10$

7 0

2 years ago

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Ms. Lynette earns $19.50 an hour when she works overtime. She worked overtime twice this week. One day she worked 3 hours of ove

algol13

(19.50*3)+(19.50*x)=146.25

8 0

2 years ago

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Select the pair of slopes that are the slopes of perpendicular lines.

agasfer [191]

<h3> $\frac{3}{4}\ and\ \frac{-4}{3}$ are the slopes of perpendicular lines</h3>

Solution:

We know that,

Product of slope of a line and slope of line perpendicular to it is always equal to -1

Option 1

$\frac{1}{2}\ and\ 2$

$Product = \frac{1}{2} \times 2 = 1$

Thus, these are not the slopes of perpendicular lines

Option 2

$\frac{3}{4}\ and\ \frac{-4}{3}\\\\Product = \frac{3}{4} \times \frac{-4}{3}\\\\Product = -1$

This option satisfies the slopes of perpendicular lines

Option 3

$\frac{-2}{5}\ and\ \frac{-5}{2}\\\\Product = \frac{-2}{5} \times \frac{-5}{2} = 1$

Thus, these are not the slopes of perpendicular lines

Option 4

2 and 2

Product = 2 x 2 = 4

Thus, these are not the slopes of perpendicular lines

7 0

2 years ago

Researchers at the Centers for Disease Control and Prevention have been studying the decay pattern of a new virus with a decay r

Andrei [34K]

Answer:

They will find 69 viruses in 8 hours.

Step-by-step explanation:

The number of viruses after t hours is given by the following equation:

$V(t) = V(0)(1-r)^{t}$

In which V(0) is the initial number of viruses and r is the decay rate, as a decimal.

They start with 500 viruses

This means that $V(0) = 500$

Decay rate of 22% per hour.

This means that $r = 0.22$

$V(t) = V(0)(1-r)^{t}$

$V(t) = 500(1-0.22)^{t}$

$V(t) = 500(0.78)^{t}$

How many viruses will they find in 8 hours?

This is V(8).

$V(t) = 500(0.78)^{t}$

$V(8) = 500(0.78)^{8}$

$V(8) = 68.51$

Rounding to the nearest whole number

They will find 69 viruses in 8 hours.

3 0

2 years ago

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