Answer:
x = 3/2 or x = -4
Step-by-step explanation:
The identifiable error the students have is that before the left hand side of the equation is factorized, the right hand side value of 12 ought to be brought to the left hand side, leaving a net value of zero on the right hand side. Then whatever is factored on the left hand side is then equated to zero and then we can find the two values of x after setting each of the individual factors to zero
We proceed as follows;
Answer:
no writting shown but
Step-by-step explanation:
i guess its super cool encouragement is the most
Answer:
Step-by-step explanation:
Represent the length of one side of the base be s and the height by h. Then the volume of the box is V = s^2*h; this is to be maximized.
The constraints are as follows: 2s + h = 114 in. Solving for h, we get 114 - 2s = h.
Substituting 114 - 2s for h in the volume formula, we obtain:
V = s^2*(114 - 2s), or V = 114s^2 - 2s^3, or V = 2*(s^2)(57 - s)
This is to be maximized. To accomplish this, find the first derivative of this formula for V, set the result equal to 0 and solve for s:
dV
----- = 2[(s^2)(-1) + (57 - s)(2s)] = 0 = 2s^2(-1) + 114s - 2s^2
ds
Simplifying this, we get dV/ds = -4s^2 + 114s = 0. Then either s = 28.5 or s = 0.
Then the area of the base is 28.5^2 in^2 and the height is 114 - 2(28.5) = 57 in
and the volume is V = s^2(h) = 46,298.25 in^3
The second one is d 78 and 82
