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Dafna11 [192]
3 years ago
12

Explique como são gravados (escrita) os bits zero ou um no HD.

Computers and Technology
1 answer:
rodikova [14]3 years ago
8 0

Answer:

The following are the description of storing bits into Hard-disk.

Explanation:

As we know computer only know the binary language, that is in the form of zero's and once's "0's and 1's". In the hard drive, it requires a magnetically covered rotating disc, that's  "head" passes over its platter.

  • It marked 0's and 1's on the platter as tiny electronic areas in the north.
  • Its head goes to the very same location to read its information again, the north and south places pass there and assume from the 0s and 1s which are contained.

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5 0
3 years ago
1.
Vlad1618 [11]
A. Since it tells about how people think she’s lesser because she’s a women.
7 0
3 years ago
Given an array as follows
slava [35]

Answer:

1) Method calcTotal:

  1. public static long calcTotal(long [][] arr2D){
  2.        long total = 0;
  3.        
  4.        for(int i = 0; i < arr2D.length; i++ )
  5.        {
  6.            for(int j = 0; j < arr2D[i].length; j++)
  7.            {
  8.                total = total + arr2D[i][j];
  9.            }
  10.        }
  11.        
  12.        return total;
  13.    }

Explanation:

Line 1: Define a public method <em>calcTotal</em> and this method accept a two-dimensional array

Line 2: Declare a variable, total, and initialize it with zero.

Line 4: An outer for-loop to iterate through every rows of the two-dimensional array

Line 6: An inner  for-loop to iterate though every columns within a particular row.

Line 8: Within the inner for-loop, use current row and column index, i and j, to repeatedly extract the value of each element in the array and add it to the variable total.

Line 12: Return the final total of all the element values as an output

Answer:

2) Method calcAverage:

  1. public static double calcAverage(long [][] arr2D){
  2.        double total = 0;
  3.        int count = 0;
  4.        
  5.        for(int i = 0; i < arr2D.length; i++ )
  6.        {
  7.            for(int j = 0; j < arr2D[i].length; j++)
  8.            {
  9.                total = total + arr2D[i][j];
  10.                count++;
  11.            }
  12.            
  13.        }
  14.        
  15.        double average = total / count;
  16.        
  17.        return average;
  18.    }

Explanation:

The code in method <em>calcAverage</em> is quite similar to method <em>calcTotal</em>. We just need to add a counter and use that counter as a divisor of total values to obtain an average.

Line 4: Declare a variable, count, as an counter and initialize it to zero.

Line 11: Whenever an element of the 2D array is added to the total, the count is incremented by one. By doing so, we can get the total number of elements that exist in the array.

Line 16: Use the count as a divisor to the total to get average

Line 18: Return the average of all the values in the array as an output.

Answer:

3) calcRowAverage:

  1. public static double calcRowAverage(long [][] arr2D, int row){
  2.        double total = 0;
  3.        int count = 0;
  4.        
  5.        for(int i = 0; i < arr2D.length; i++ )
  6.        {
  7.            if(i == row)
  8.            {
  9.                for(int j = 0; j < arr2D[i].length; j++)
  10.                {
  11.                    total = total + arr2D[i][j];
  12.                    count++;
  13.                }
  14.            }
  15.            
  16.        }
  17.        
  18.        double average = total / count;
  19.        
  20.        return average;
  21.    }

Explanation:

By using method <em>calcAverage </em>as a foundation, add one more parameter, row, in the method <em>calcRowAverage</em>. The row number is used as an conditional checking criteria to ensure only that particular row of elements will be summed up and divided by the counter to get an average of that row.

Line 1: Add one more parameter, row,

Line 8-15: Check if current row index, i, is equal to the target row number, proceed to sum up the array element in that particular row and increment the counter.

5 0
3 years ago
What is a project?
Elan Coil [88]
Simply put, a project is a series of tasks that need to be completed in order to reach a specific outcome. A project can also be defined as a set of inputs and outputs required to achieve a particular goal. Projects can range from simple to complex and can be managed by one person or a hundred.
5 0
3 years ago
Read 2 more answers
Write a program that assigns a value the value of 50000 to an integer variable x, assigns the value of x*x to an integer variabl
Allushta [10]

Answer:

Explanation:

The following code is written in Java and does exactly what the question asks. The variables are long variables instead of integers because integer variables can only be a maximum of 2147483647 and the product of these two variables is much higher than that.

public static void main(String args[]) {

               long x = 50000;

               long y = x * x;

               System.out.println(y);

       }

7 0
3 years ago
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