Step-by-step explanation:
Let the sample space be S
S= {1, 2, 3, 4, 5, 6, 7, 8, 9, 10}
Let A be the event of getting 6.
A = {6}
Let B be the event of getting a number greater than 3.
B = {4, 5, 6, 7, 8, 9, 10}
Answer:
x = 3
using the mid segment formula since quadrilateral WZYP is similar to that of MZYT, this is expressed as;
29 = 1/2(23 +11x+2)
Cross multiply
2(29) = 23+11x+2
58 = 25 + 11x
11x = 58 - 25
11x = 33
Divide both sides by 11
11x/11 = 33/11
Hence the value of x is 3
15.12
That's the a water to ur question.
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