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elena-14-01-66 [18.8K]
4 years ago
12

Can someone answer this question quickly? thanks

Mathematics
1 answer:
kirill115 [55]4 years ago
5 0

Step-by-step explanation:

Let the sample space be S

S= {1, 2, 3, 4, 5, 6, 7, 8, 9, 10}

\therefore n(S) = 10

Let A be the event of getting 6.

A = {6}

\therefore n(A) = 1\\P(A) = \frac{n(A)}{n(S)} = \frac{1}{10}

Let B be the event of getting a number greater than 3.

B = {4, 5, 6, 7, 8, 9, 10}

\therefore n(B) = 7\\P(B) = \frac{n(B)}{n(S)} = \frac{7}{10}

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Luba_88 [7]

Answer:

We know that the equation of the circle in standard form is equal to <em>(x-h)² + (y-k)² = r²</em> where (h,k) is the center of the circle and r is the radius of the circle.

We have x² + y² + 8x + 22y + 37 = 0, let's get to the standard form :

1 - We first group terms with the same variable :

(x²+8x) + (y²+22y) + 37 = 0

2 - We then move the constant to the opposite side of the equation (don't forget to change the sign !)

(x²+8x) + (y²+22y) = - 37

3 - Do you recall the quadratic identities ? (a+b)² = a² + 2ab + b². Now that's what we are trying to find. We call this process <u><em>"completing the square"</em></u>.

x²+8x = (x²+8x + 4²) - 4² = (x+4)² - 4²

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(x+4)² - 4² + (y+22)² - 11² = -37

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Answer:

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<u>As two angles and one side is congruent, the triangles are also congruent:</u>

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<u>The quadrilateral has area of:</u>

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