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Step2247 [10]
3 years ago
11

Is (x+4)^2 equivalent to 2x^2+8x+8? Explain or show your reasoning.

Mathematics
1 answer:
Zolol [24]3 years ago
8 0

Answer:

It's wrong because the y intercepts are different

Step-by-step explanation:

The box method is OP for these kind of questions

If I don't do a good job explaining it then I reccomend you consult the internet

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If Enguun tutored for 19.5 hours last month, how much money did she earn last month?
Lunna [17]
Uhh
how much money does enguun earn for every hour she works?
6 0
3 years ago
A parking lot costs $1300 a month to operate, and it spends $260 each
serg [7]

Answer:

p = 190n - 1300

Step-by-step explanation:

Given

Monthly  = 1300

Expenses = 260 per car

Charges = 450 per car

Required

Determine the profit

Let the number of cars be n. So:

Express on n cars is: 260n

Charges on n cars is 450n

The profit (p) is then represented as:

p = Charges - Expenses - Monthly\ Expenses

p = 450n - 260n - 1300

p = 190n - 1300

6 0
3 years ago
Given the function f(x) = 0.5 |x– 4| – 3, for what values of x is f(x) =7
Sladkaya [172]

Answer:

-16,24  B

Step-by-step explanation:

To solve this simplify the equation until it's just the absolute value brackets

7=.5 |x-4|-3

Add 3 to both sides and divide by .5 to get

20=|x-4|

Then solve this equation where the leftmost side is a positive and then a negative

So 20=x-4  

x=24

24 is one of our answers

Then solve it when the left side is a negative

-20=x-4

x=-16 which is the other answer

7 0
3 years ago
A machine that is programmed to package exactly 1.20 pounds of cereal is being tested for its accuracy. Assume that the populati
Sav [38]

Answer:

Step-by-step explanation:

Hello!

To test the accuracy of a machine said to package exactly 1.20 pounds od cereal a random sample of 36 cereal boxes was taken.

The study variable is:

X: Weight of a cereal box.

This variable has no known distribution but it's population standard deviation is known σ= 0.66 pounds.

The sample weight is X[bar]= 1.48 pounds.

a.

The claim is that the machine packages exactly 1.20 pounds per box and the parameter of interest is the population mean, so you have to test is the population mean weight packaged by the machine is 1.20 pounds or not, symbolically:

H₀: μ = 1.20

H₁: μ ≠ 1.20

b.

As I said before there is no information about the distribution of the study variable so I'll apply the Central Limit Theorem to approximate the distribution of the sample proportion to normal.

Remember: Be a population with probability function f(X;μ,δ²) from which a random sample of size n is selected. Then the distribution of the sample means tends to the normal distribution with mean μ and variance δ²/n when the sample size tends to infinity.

As a rule, a sample of size greater than or equal to 30 is considered sufficient to apply the theorem and use the approximation.

Then we can use the standard normal as a statistic for the test:

Z= \frac{X[bar]-Mu}{\frac{Sigma}{\sqrt{n} } }≈N(0;1)

Z_{H_0}= \frac{1.48-1.20}{\frac{0.66}{\sqrt{36} } } = 2.54

c.

The level of significance of this test is α: 0.10

The critical is two-tailed, wich means you will have two critical values:

Critical value 1: Z_{\alpha /2} = Z_{0.1/2} = Z_{0.05}= -1.648

Critical value 1: Z_{1-\alpha /2}= Z_{1-(0.1/2)}= Z_{0.95}= 1.648

This means that you will reject the null hypothesis if  Z_{H_0} ≤ -1.648 or if Z_{H_0} ≥ 1.648.

You will not reject the null hypothesis if -1.648 ≤ Z_{H_0} ≤ 1.648.

d.

Z_{H_0} is greater than the upper critical value, so the decision is to reject the null hypothesis.

Using 10% confidence level there is enough statistical evidence to conclude that the population average weight of the cereal boxes is different from 1.2 pounds.

I hope it helps!

3 0
3 years ago
Find the least common of 2x^2 and 4x+12
Tasya [4]

Answer:

2 can be taken out of both so the LCD is 2

Step-by-step explanation:

7 0
3 years ago
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