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Elan Coil [88]
2 years ago
6

X=y+8 and x=5y+12 (x,y)

Mathematics
1 answer:
Kipish [7]2 years ago
4 0

3 x + 2 y + z x + y + z   ,  x = 2  ,  y = 3  ,  z = 1 tan ( x )  ,  x = − π 3 x + 2 y + z  ,  x = 2  ,  y = 3  ,  z = 1

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What is the value of 5 in the number 583.2
GarryVolchara [31]

Answer:500.0

Step-by-step explanation:

Hundred.Since the 5 isn’t a decimal meaning it doesn’t have the “th” at the end of the word and the 5 is clearly on the hundred.

How this helps :)

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8 0
3 years ago
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Carter is going to invest $79000 and leave it in an account for 12 years. Assuming the interest is compounded continuously, what
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r≈3.55%

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3 years ago
What is the slope of the line that passes through (2,6) and (6,9)
Alenkasestr [34]

Answer:

3,3

Step-by-step explanation:

6 0
3 years ago
BRAINIEST TO WHOEVER RIGHT
Anna35 [415]

Could you get a closer picture?

7 0
3 years ago
Use the mid-point rule with n = 4 to approximate the area of the region bounded by y = x3 and y = x. (10 points)
USPshnik [31]
See the graph attached.

The midpoint rule states that you can calculate the area under a curve by using the formula:
M_{n} = \frac{b - a}{2} [ f(\frac{x_{0} + x_{1} }{2}) +  f(\frac{x_{1} + x_{2} }{2}) + ... +  f(\frac{x_{n-1} + x_{n} }{2})]

In your case:
a = 0
b = 1
n = 4
x₀ = 0
x₁ = 1/4
x₂ = 1/2
x₃ = 3/4
x₄ = 1

Therefore, you'll have:
M_{4} = \frac{1 - 0}{4} [ f(\frac{0 +  \frac{1}{4} }{2}) +  f(\frac{ \frac{1}{4} + \frac{1}{2} }{2}) +  f(\frac{\frac{1}{2} + \frac{3}{4} }{2}) + f(\frac{\frac{3}{4} + 1} {2})]
M_{4} = \frac{1}{4} [ f(\frac{1}{8}) +  f(\frac{3}{8}) +  f(\frac{5}{8}) + f(\frac{7}{8})]

Now, to evaluate your f(x), you need to look at the graph and notice that:
f(x) = x - x³

Therefore:
M_{4} = \frac{1}{4} [(\frac{1}{8} - (\frac{1}{8})^{3}) + (\frac{3}{8} - (\frac{3}{8})^{3}) + (\frac{5}{8} - (\frac{5}{8})^{3}) + (\frac{7}{8} - (\frac{7}{8})^{3})]

M_{4} = \frac{1}{4} [(\frac{1}{8} - \frac{1}{512}) + (\frac{3}{8} - \frac{27}{512}) + (\frac{5}{8} - \frac{125}{512}) + (\frac{7}{8} - \frac{343}{512})]

M₄ = 1/4 · (2 - 478/512)
     = 0.2666

Hence, the <span>area of the region bounded by y = x³ and y = x</span> is approximately 0.267 square units.

6 0
3 years ago
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