![\sqrt[3]{\dfrac{-27}{125}} = -\sqrt[3]{\left(\dfrac{3}{5}\right)^{3}}=\dfrac{-3}{5}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B%5Cdfrac%7B-27%7D%7B125%7D%7D%20%3D%20-%5Csqrt%5B3%5D%7B%5Cleft%28%5Cdfrac%7B3%7D%7B5%7D%5Cright%29%5E%7B3%7D%7D%3D%5Cdfrac%7B-3%7D%7B5%7D)
The appropriate choice appears to be ...
B. -3/5
Multiply 2/3 by the reciprocal, 3/2, on both sides.
Answer:
The answer is It is between 0 and 1
Step-by-step explanation:
If you solve the problem step by step as (-2^3)^-2<1 then it comes out as true so it would be less than 1 but more then 0.
Answer:
C^-3+d^5/f^3+g^-7
Step-by-step explanation:
The answer is as seen above
Answer:
5/6
Step-by-step explanation:
5/10 can be simplified as 1/2
1/2 + 1/3 = 3/6 + 2/6 = 5/6