The coefficients in the balanced reaction
<u>4</u> Fe + <u>3</u> O₂ → <u>2</u> Fe₂O₃
represent the ratio of moles of each reactant to each product. That is, for every 4 moles of Fe and 3 moles of O₂, 2 moles of Fe₂O₃ are produced.
First convert the given amount of Fe into moles. Fe has a molar mass of 55.845 g/mol, so you have
42.7 g × (1/55.845 mol/g) = 0.765 mol
of Fe.
Find how many moles of Fe₂O₃ are produced given this much Fe and an abundant supply of O₂. Multiply the coefficients of the balanced reaction by 0.765/4 :
<u>0.765</u> Fe + <u>0.573</u> O₂ → <u>0.382</u> Fe₂O₃
Now convert the amount of Fe₂O₃ to grams. O has a molar mass of 15.999 g/mol, so Fe₂O₃ has a total molar mass of about
2 (55.845 g/mol) + 3 (15.999 g/mol) = 159.687 g/mol
Then the reaction would produce about
0.382 mol × (158.687 g/mol) ≈ 61.0 g
of Fe₂O₃.
The answer to your question is C.
You have to take the amount of money payed, which in this case is 45.50, and divide it with 7.
100,000+200+3, You must add each property.
