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Wewaii [24]
3 years ago
6

Gavin and his three friends want to share 1/3of cake equally. Gavin says that each friend will get 1/9 of the cake. Use the drop

-down menus to explain weather or not Gavin is correct
Mathematics
2 answers:
Alexxandr [17]3 years ago
6 0

Answer: Incorrect

Step-by-step explanation:

Given

Gavin and his three friends wants to share \frac{1}{3} of cake equally.

So, there are 4 members to distribute the cake

Each member will get

\Rightarrow \dfrac{\dfrac{1}{3}}{4}\\\\\Rightarrow \dfrac{1}{3\times 4}=\dfrac{1}{12}

So, each member get one-twelvefth of the given cake.

Hence, Gavin is  incorrect.

Digiron [165]3 years ago
4 0

Answer:

Gavin is incorrect.

Step-by-step explanation:

He divides 1/3 by 3 people. When he should divide by 4 people, including himself. 1/3 / 4 = 1/3 * 1/4= 1/12

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15 is (hopefully) the correct answer!

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Identify the relationship then solve for x
kupik [55]

These are alternate interior angles.

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10x=9x+7

subtract 9x from 10x.

x=7

the answers are bolded.

I hope this helps

5 0
3 years ago
A brand new truck was purchased for $45.000. A year later the truck was worth $40,480, and the year after that $35.622. If the r
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Answer $32,045

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The rate of depreciation: 1.1116

If you do $45,000 divided by 1.1116 you'll get 40,322.

It won't be the exact same answer because you would have to divide for an hour.

Now we can skip to the important part: $35,622 divided by 1.1116 = $32,045

Therefore the truck will be worth $32,045 in 10 years!

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6 0
3 years ago
A certain number of sixes and nines is added to give a sum of 126; if the number of sixes and nines is interchanged, the new sum
galina1969 [7]

Answer:

Original number of sixes = 6

Original number of nines = 10

Step-by-step explanation:

We are told in the question that:

A certain number of sixes and nines is added to give a sum of 126

Let us represent originally

the number of sixes = a

the number of nines = b

Hence:

6 × a + 9 × b = 126

6a + 9b = 126.....Equation 1

If the number of sixes and nines is interchanged, the new sum is 114.

For this second part, because it is interchanged,

Let us represent

the number of sixes = b

the number of nines = a

6 × b + 9 × a = 114

6b + 9a = 114.......Equation 2

9a + 6b = 114 .......Equation 2

6a + 9b = 126.....Equation 1

9a + 6b = 114 .......Equation 2

We solve using Elimination method

Multiply Equation 1 by the coefficient of a in Equation 2

Multiply Equation 2 by the coefficient of a in Equation 1

6a + 9b = 126.....Equation 1 × 9

9a + 6b = 114 .......Equation 2 × 6

54a + 81b = 1134 ........ Equation 3

54a + 36b = 684.........Equation 4

Subtract Equation 4 from Equation 3

= 45b = 450

divide both sides by b

45b/45 = 450/45

b = 10

Therefore, since the original the number of nines = b,

Original number of nines = 10

Also, to find the original number of sixes = a

We substitute 10 for b in Equation 1

6a + 9b = 126.....Equation 1

6a + 9 × 10 = 126

6a + 90 = 126

6a = 126 - 90

6a = 36

a = 36/6

a = 6

Therefore, the original number of sixes is 6

7 0
3 years ago
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