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3 years ago

F(x)=(x-2)(x+1)/x+1 at which values of x does the graph of have a vertical asymptote?

Mathematics

2 answers:

sergey [27]3 years ago

7 0

Answer:

As x → ∞ , y → ∞

As x → -∞ , y → -∞

Step-by-step explanation:

We can easily solve this equation by using a graphing calculator or plotting tool

The function is

f(x)=(x-2)(x+1)/x + 1

Please, see image attached.

The graph has a vertical asymptote at x = 0

As x → ∞ , y → ∞

As x → -∞ , y → -∞

Hatshy [7]3 years ago

3 0

Answer: It is B and F

Step-by-step explanation: on edge

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ASAP Plz what is the value of x? Plz no joking around this is from quiz 4.09: Special Right Triangles 2

Sunny_sXe [5.5K]

Ooh this is a good one!
Firstly, let's find RT so that we can solve the top triangle.
We could actually use 3 methods to find this side: 1) trig to find RT
2) trig to find ST, then Pythagorean Theorem to determine RT
3) use the special 30-60-90 right triangle rule ... hmm, I'm going with the last because it's easiest ;)

For 30-60-90 triangles, the sides are always as follows: smallest side (opposite the 30) is s, the middle side is sSR3, and the hypotenuse is 2×s
Thus, since we have the side opposite 60, it is = sSR3, so:
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Secondly, we are looking at the other type of special right triangle, the 45-45-90:
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3 years ago

Read 2 more answers

The length of the hypotenuse of a right triangle is 24. If the length of one leg is 8, what is approximate length of the other l

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Something that a right triangle is characterised by is the fact that we may use Pythagoras' theorem to find the length of any one of its sides, given that we know the length of the other two sides. Here, we know the length of the hypotenuse and one other side, therefor we can easily use the theorem to solve for the remaining side.

Now, Pythagoras' Theorem is defined as follows:

c^2 = a^2 + b^2, where c is the length of the hypotenuse and a and b are the lengths of the other two sides.

Given that we know that c = 24 and a = 8, we can find b by substituting c and a into the formula we defined above:

c^2 = a^2 + b^2

24^2 = 8^2 + b^2 (Substitute c = 24 and a = 8)

b^2 = 24^2 - 8^2 (Subtract 8^2 from both sides)

b = √(24^2 - 8^2) (Take the square root of both sides)

b = √512 (Evaluate 24^2 - 8^2)

b = 16√2 (Simplify √512)

= 22.627 (to three decimal places)

I wasn't sure about whether by 'approximate length' you meant for the length to be rounded to a certain number of decimal places or whether you were meant to do more of an estimate based on your knowledge of surds and powers. If you need any more clarification however don't hesitate to comment below.

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3 years ago

F(x)=(x-2)(x+1)/x+1 at which values of x does the graph of have a vertical asymptote?​

F(x)=(x-2)(x+1)/x+1 at which values of x does the graph of have a vertical asymptote?