Answer:
The height above sea level at <em>B</em> is approximately 1,604.25 m
Step-by-step explanation:
The given length of the mountain railway, AB = 864 m
The angle at which the railway rises to the horizontal, θ = 120°
The elevation of the train above sea level at <em>A</em>, h₁ = 856 m
The height above sea level of the train when it reaches <em>B</em>, h₂, is found as follows;
Change in height across the railway, Δh = AB × sin(θ)
∴ Δh = 864 m × sin(120°) ≈ 748.25 m
Δh = h₂ - h₁
h₂ = Δh + h₁
∴ h₂ ≈ 856 m + 748.25 m = 1,604.25 m
The height above sea level of the train when it reaches <em>B</em> ≈ 1,604.25 m
The answer should be the first one exponential
The supplement of < 72 has the same measure as < (4x + 8). Therefore, < (4x + 8) must equal 108°. We can establish the following equality statement to solve for x:
< (4x + 8) + < 72° = 180°
Combine like terms:
4x + 80 = 180°
Subtract 80 from both sides:
4x + 80° - 80° = 180° - 80°
4x = 100
Divide both sides by 4 to solve for x:
4x/4 = 100/4
x = 25
To verify whether the value of x is correct, substitute its value into the equality statement:
< (4x + 8)° + < 72° = 180°
< [4(25) + 8]° + < 72° = 180°
< (100 + 8)° + < 72° = 180°
< 108° + < 72° = 180°
180° = 180° (True statement. Therefore, the correct answer is x = 25).
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Answer:
a)6
b)v^2-u^2/2a
Step-by-step explanation:
a)Given that,
u=12
a= -6
s=9
We know that,
v^2=u^2+2as
or, v^2=(12)^2+2×(-6)×9
or,v^2=144-108
or,v^2=36
or, v=√36
∴v=6
(Ans)
b)If ,v^2=u^2+2as
then, u^2+2as=v^2
or,2as=v^2-u^2
or, s=v^2-u^2/2a
∴s=v^2-u^2/2a
Hope ya find it helpful.. Thanks a lot...
2.000 pluse 4.00=600.000
4 pluse 2=6
thousand pluse hundreds=hundre thousandths
