<h3>Answer:</h3>
x = 3
<h3>Explanation:</h3>
The product of the lengths of segments from the intersection point to the circle is the same for both secants.
... 1×6 = 2×x
... 6/2 = x = 3 . . . . . divide by 2
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<em>Comment on secant geometry</em>
Interestingly, this relation is true whether the point of intersection of the secants is inside the circle or outside.
When it is outside, the product is of the distance to the near intersection with the circle and the distance to the far intersection with the circle.
Let x = # of 25-cent stamps
y = # of 2-cent stamps
{ x+ y = 88
{ 0.25x + 0.02y = 15.56
60 25-cent stamps 28 2-cent stamps
Help?? I need that question to but just that the weight instead of being 1000 is 2000
<h3>
Answer: 680 different combinations</h3>
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Explanation:
If order mattered, then we'd have 17*16*15 = 4080 different permutations. Notice how I started with 17 and counted down 1 at a a time until I had 3 slots to fill. We count down by 1 because each time we pick someone, we can't pick them again.
So we have 4080 different ways to pick 3 people if order mattered. But again order doesn't matter. All that counts is the group itself rather than the individual or how they rank. There are 3*2*1 = 6 ways to order any group of three people, which means there are 4080/6 = 680 different combinations possible.
An alternative is to use the nCr formula with n = 17 and r = 3. That formula is

where the exclamation marks indicate factorials
Answer:
2 one and the 4 one
Step-by-step explanation: