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3 years ago

Perform the operation below using a number line. -7-(-8). ASAP. pleeease help.

Mathematics

1 answer:

Aliun [14]3 years ago

4 0

Answer:

Step-by-step explanation:

Calculation steps:

-7-(-8) = ⇒ two negatives cancel and change to positive

- 7 + 8 = ⇒ 8-7 = 1

1 ⇒ answer

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Factor completely x2 + 20x − 36.

vodomira [7]

Answer:

Prime

Step-by-step explanation:

x² + 20x − 36

You must find a pair of numbers that multiply to give -36 and add to give +20.

The likely candidates are 2 and 18, and they must have opposite signs to give a negative product.

+2 × (-18) = -36; +2 + (-18) = -16

-2 × 18 = -36; -2 + 8 = +16

Neither combination gives +20 as the sum.

The expression can't be factored with rational numbers.

The expression is prime.

5 0

3 years ago

Let represent the number of tires with low air pressure on a randomly chosen car. The probability distribution of is as follows.

Sindrei [870]

Answer:

a) $P(X=3) = 0.1$

b) $P(X\geq 3) =1-P(X$

And replacing we got:

$P(X \geq 3) = 1- [0.2+0.3+0.1]= 0.4$

c) $P(X=4) = 0.3$

d) $P(X=0) = 0.2$

e) $E(X) =0*0.2 +1*0.3+2*0.1 +3*0.1 +4*0.3= 2$

f) $E(X^2)= \sum_{i=1}^n X^2_i P(X_i)$

And replacing we got:

$E(X^2) =0^2*0.2 +1^2*0.3+2^2*0.1 +3^2*0.1 +4^2*0.3= 6.4$

And the variance would be:

$Var(X0 =E(X^2)- [E(X)]^2 = 6.4 -(2^2)= 2.4$

And the deviation:

$\sigma =\sqrt{2.4} = 1.549$

Step-by-step explanation:

We have the following distribution

x 0 1 2 3 4

P(x) 0.2 0.3 0.1 0.1 0.3

Part a

For this case:

$P(X=3) = 0.1$

Part b

We want this probability:

$P(X\geq 3) =1-P(X$

And replacing we got:

$P(X \geq 3) = 1- [0.2+0.3+0.1]= 0.4$

Part c

For this case we want this probability:

$P(X=4) = 0.3$

Part d

$P(X=0) = 0.2$

Part e

We can find the mean with this formula:

$E(X)= \sum_{i=1}^n X_i P(X_i)$

And replacing we got:

$E(X) =0*0.2 +1*0.3+2*0.1 +3*0.1 +4*0.3= 2$

Part f

We can find the second moment with this formula

$E(X^2)= \sum_{i=1}^n X^2_i P(X_i)$

And replacing we got:

$E(X^2) =0^2*0.2 +1^2*0.3+2^2*0.1 +3^2*0.1 +4^2*0.3= 6.4$

And the variance would be:

$Var(X0 =E(X^2)- [E(X)]^2 = 6.4 -(2^2)= 2.4$

And the deviation:

$\sigma =\sqrt{2.4} = 1.549$

4 0

3 years ago

Let f(x)=x^2+5x−36. Enter the x-intercepts of the quadratic function in the boxes.___and__

Zolol [24]

Given

$f(x)=x^2+5x-36$

8 0

1 year ago

n a call center the number of received calls in a day can be modeledby a Poisson random variable. We know that, on average, 0.5%

guapka [62]

Answer:Pois(ln(200))

Step-byy-step explanation:

Let N be the number of received calls in a day

That is

N∼Pois(λ).

0.5% = 0.5/100 = 1/200 of no calls

P(N=0)=e^−λ=1/200

-λ=e^(1/200)

λ=in(200)

Our number of calls in a day is distributed Pois(ln(200)).

7 0

3 years ago

Read 2 more answers

Please help with the questions in the image

allochka39001 [22]

Answer:

fghjk

Step-by-step explanation:

6 0

3 years ago

Perform the operation below using a number line. -7-(-8). ASAP. pleeease help.​

Perform the operation below using a number line. -7-(-8). ASAP. pleeease help.