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2 years ago

Find the equation of the line that passes through point (6, 1) with the x-intercept of 2.

Mathematics

1 answer:

dedylja [7]2 years ago

4 0

$y = \frac{ - 1}{4} x + \frac{1}{2}$

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This extreme value problem has a solution with both a maximum value and a minimum value. use lagrange multipliers to find the ex

noname [10]

$L(x,y,z,\lambda)=10x+10y+2z+\lambda(5x^2+5y^2+2z^2-42)$

$L_x=10+10\lambda x=0\implies1+\lambda x=0$

$L_y=10+10\lambda y=0\implies1+\lambda y=0$

$L_z=2+4\lambda z=0\implies1+2\lambda z=0$

$L_\lambda=5x^2+5y^2+2z^2-42=0$

$\begin{cases}L_x=0\\L_y=0\\L_z=0\end{cases}\implies1+\lambda x=1+\lambda y=1+2\lambda z=0\implies x=y=2z$

$5x^2+5y^2+2z^2=5(2z)^2+5(2z)^2+2z^2=42z^2=42\implies z^2=1$

$z^2=1\implies z=\pm1\implies x=y=\pm2$

There are two critical points, at which we have

$f\left(2,2,1\right)=42\text{ (a maximum value)}$

$f\left(-2,-2,-1\right)=-42\text{ (a minimum value)}$

3 0

3 years ago

Help Please . its due in 5 hours and i cant find answers

dolphi86 [110]

Answer:

39 pi cubic inches

Step-by-step explanation:

The volume of a cone is (1/3)(area of the base)(height).

$V=\frac{1}{3}Bh$

Find the area of the circular base. The circumference of a circle is $C=2\pi r$ , so

$2\pi r = 6\pi\\\\r=3$

Now that you know the radius of the circular base, you can find its area:

$A=\pi r^2 = \pi(3^2)=9\pi$

The height of the cone is 13. Time to use the volume formula.

$V=\frac{1}{3}Bh\\\\V=\frac{1}{3}(9\pi)(13)\\\\V=39\pi$

6 0

3 years ago

Write the integer that best represents 23 degrees below zero

snow_tiger [21]

The integer would be -23

5 0

3 years ago

Read 2 more answers

Which is the graph of f(x)=3/2(1/3)x^

Eddi Din [679]

Answer:

havent got tought this yet sorry wish i can help

5 0

2 years ago

What value of h makes the statement true? (17+h)+(–9) = 17+(5+(–9))

aalyn [17]

I know this is late and you probably got the answer but just in case its C. 5. :P

5 0

3 years ago