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s344n2d4d5 [400]
2 years ago
8

Find the equation of the line that passes through point (6, 1) with the x-intercept of 2.

Mathematics
1 answer:
dedylja [7]2 years ago
4 0

y =  \frac{ - 1}{4} x +  \frac{1}{2}

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Please guys help me. I will give you the brainliest if you give me the correct answers. ​
andrey2020 [161]

Answer:

vbvcfvbnbvcxcvbnvcxvbnmbvcvbvfdfgbhnbgvfgvbnbgfghbnbgvfgvbnbgfgbngfgbgfgfgfgfgfgfgfgfgfgfgrrrdrd

Step-by-step explanation:

3 0
3 years ago
If the rectangular menu is 3 feet long by 2 feet wide , what is the area of the menu?
Bess [88]

area = length * width

       = 3 * 2

  = 6 ft ^2

4 0
3 years ago
Solve the inequality if possible 4(3-2x)>2(6-4x)
GenaCL600 [577]

Final Answer: No Solution

Steps/Reasons/Explanation:

Question: 4(3-  2x) > 2(6-  4x)

<u>Step 1</u>: Divide both sides by 2.

2(3 - 2x) > 6 - 4x

<u>Step 2</u>: Expand.

6 - 4x > 6 - 4x

<u>Step 3</u>: Since 6 - 4x > 6 - 4x is false, we have no solution.

No Solution

~I hope I helped you :)~

6 0
3 years ago
Read 2 more answers
PLS HURRY Point S is translated 5 units to the left and 12 units up to create point S'. Find the distance between point S and po
svet-max [94.6K]

Given:

Point S is translated 5 units to the left and 12 units up to create point S'.

To find:

The distance between the points S and S'.

Solution:

Point S is translated 5 units to the left and 12 units up to create point S'.

The diagram for the given problem is shown below.

From the below figure it is clear that the distance between the point S and S' is the height of a right triangle whose legs are 5 units and 12 units.

By Pythagoras theorem,

Hypotenuse^2=Perpendicular^2+Base^2

SS'^2=(12)^2+(5)^2

SS'^2=144+25

SS'^2=169

Taking square root on both sides.

SS'=\sqrt{169}

SS'=13

Therefore, the distance between S and S' is 13 units.

8 0
3 years ago
Find the product for 56.44
miv72 [106K]

Step-by-step explanation:

55.44=2464

mark as brainliest

8 0
3 years ago
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