Answer:
f(x)^-1=x+12
Step-by-step explanation:
f(x)=x-12
y=x-12
x=y-12
y=x+12
f(x)^-1=x+12
Hope it helps.
Actually Welcome to the concept of expo functions.
f(x) = -8(2)^x - 12 ,
for f(0) ,here substitute x = 0
so we get as ,
==> f(0) = -8(2)^0 -12
==> f(0) = -8-12
==> f(0) = -20
hence, f(0) = -20
Answer:
y ≤-7
Step-by-step explanation:
-8y ≥56
Divide each side by -8. Remember to flip the inequality
-8y/-8 ≤56/-8
y ≤-7
The vertex<span> of a </span>parabola<span> is the point where the </span>parabola<span> crosses its axis of symmetry. If the coefficient of the x 2 term is positive, the </span>vertex<span> will be the lowest point on the graph, the point at the bottom of the “ U ”-shape.
</span><span>
The vertex of the parabola whose equation is y = x^2 + 8 x + 12 will be :
</span>(x , y) = (-4,-4)
