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loris [4]
3 years ago
10

2p/9 + 5p/18 - 5/6 = 2/3 + p/12 + 1/6

Mathematics
1 answer:
mezya [45]3 years ago
4 0
\frac{2p}{9}+\frac{5p}{18}-\frac{5}{6}=\frac{2}{3}+\frac{p}{12}+\frac{1}{6}\ \ \ |Multiply\ by\ 36\\\\
4*2p+2*5p-5*6=12*2+3*p+6*1\\\\
8p+10p-30=24+3p+6\\\\
18p-30=3p+30\ \ \ |Subtract\ 3p\\\\
15p-30=30\ \ \ |Add\ 30\\\\
15p=60\ \ \ |Divide\ by\ 15\\\\
\boxed{p=4}
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How do you answer this following equation “ the sum of two numbers is 33 , and the sum of 7 times the first number and 5 times t
nadya68 [22]

\bf \begin{cases} a\\\\ b \end{cases}\qquad \qquad \begin{array}{llll} \stackrel{\textit{the sum of \underline{a} and \underline{b}}}{a+b=33}\\\\ \stackrel{\textit{the sum of 7 times \underline{a} and 5 times \underline{b}}}{7a+5b=197} \end{array} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ a+b=33\implies \boxed{b}=33-a \\\\\\ \stackrel{\textit{substituting \boxed{b} in the second equation}}{7a+5\left(\boxed{33-a} \right)=197}\implies 7a+165-5a=197


\bf 2a+165=197\implies 2a=32\implies a=\cfrac{32}{2}\implies \blacktriangleright a=16 \blacktriangleleft \\\\\\ \boxed{b}=33-a\implies b=33-16\implies \blacktriangleright 17\blacktriangleleft

4 0
3 years ago
Consider the equation below .
Fudgin [204]
By using change base formula which is :
log x to the base b = (log x)/(log b) to a new base

∴ log₄(x+3) = log (x+3) / log 4
and
 log₂(2+x) = log (2+x) / log 2

∴ the correct answer is number one

See the attached figure.

3 0
3 years ago
If a cone has the same radius and height as a cylinder, the volume of the cone is
Elena L [17]

Answer:

The volume of the cone is one third to the volume of the cylinder.

Step-by-step explanation:

It is because the formula of volume of cone is 1/3 to the volume of cylinder .

Volme of cone :

v =  \frac{1}{3} \pi {r}^{2} h

Volume of cylinder :

v = \pi {r}^{2} h

3 0
3 years ago
What is the value of (3-54(2)– 16+ 2?<br> -40
Xelga [282]

Answer:

the answer to the question is =48

6 0
3 years ago
a multiple-choice test contains 8 questions. there are four possible answers for each question. in how many ways can a student a
Ulleksa [173]

There are the 105 ways with the help of combination by which the student answer the questions on the test.

According to the statement

we have to find the number of the ways can a student answer the questions on the test if the student answers every question.

So, For this purpose, we know that the

A combination is a mathematical technique that determines the number of possible arrangements in a collection of items where the order of the selection does not matter.

From the given information:

Test contains 8 questions and there are 4 possible answers.

Then we have to find the number of ways.

We use combination here which become

C^{8} _{4}

Now solve it then

C^{8} _{4} = \frac{8!}{4! * 4!}

C^{8} _{4} = \frac{8*7*6*5*4!}{4! * 4!}

C^{8} _{4} = \frac{8*7*6*5}{ 4*3*2*1}

C^{8} _{4} = {7*3*5}

Then multiply it and the answer become

105.

So, There are the 105 ways with the help of combination by which the student answer the questions on the test.

Learn more about combination here

brainly.com/question/11732255

#SPJ4

4 0
2 years ago
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