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jeka94
3 years ago
7

I will give brainliest

Mathematics
2 answers:
sertanlavr [38]3 years ago
7 0

Answer:

5^2

Step-by-step explanation:

mars1129 [50]3 years ago
4 0

Answer:

5^2 or 25

Step-by-step explanation:

5^6/5^4 = 5^2

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Answer:

96 inch²

Step-by-step explanation:

there are 2 shapes,

1. a square

2. a triangle

lets find the area of the square first,

<u>AREA = SIDE × SIDE</u>

= 8 × 8

= 64 inch²

now, area of triangle ,

area \:  =  \frac{1}{2}  \times base \:  \times height \:

=  \frac{1}{2}  \times 8 \times 8 \\  =  \frac{1}{2}  \times 64 \\  = 32 \:  {inch}^{2}

so, total area is :

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The tensile strength of a metal part is normally distributed with mean 40 pounds and standard deviation 5 pounds. If 50,000 part
nalin [4]

Answer:

a) how many would you expect to fail to meet a minimum specification limit of 35-pounds tensile strength?

7933 parts

b) How many would have a tensile strength in excess of 48 pounds?

2739.95 parts

Step-by-step explanation:

The formula for calculating a z-score is is z = (x-μ)/σ, where x is the raw score, μ is the population mean, and σ is the population standard deviation.

a) how many would you expect to fail to meet a minimum specification limit of 35-pounds tensile strength?

z = (x-μ)/σ

x = 35 μ = 40 , σ = 5

z = 35 - 40/5

= -5/-5

= -1

Determining the Probability value from Z-Table:

P(x<35) = 0.15866

Converting to percentage = 15.866%

We are asked how many will fail to meet this specification

We have 50,000 parts

Hence,

15.866% of 50,000 parts will fail to meet the specification

= 15.866% of 50,000

= 7933 parts

Therefore, 7933 parts will fail to meet the specifications.

b) How many would have a tensile strength in excess of 48 pounds?

z = (x-μ)/σ

x = 48 μ = 40 , σ = 5

z = 48 - 40/5

z = 8/5

z = 1.6

P-value from Z-Table:

P(x<48) = 0.9452

P(x>48) = 1 - P(x<48)

1 - 0.9452

= 0.054799

Converting to percentage

= 5.4799%

Therefore, 5.4799% will have an excess of (or will be greater than) 48 pounds

We are asked, how many would have a tensile strength in excess of 48 pounds?

This would be 5.4799% of 50,000 parts

= 5.4799% × 50,000

= 2739.95

Therefore, 2739.95 parts will have a tensile strength excess of 48 pounds

4 0
3 years ago
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