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sergey [27]
2 years ago
14

Five more than the quotient of a number and 4 is equal to 9

Mathematics
2 answers:
Vadim26 [7]2 years ago
8 0

Answer: n=16 or 5+n/4=9

Step-by-step explanation:

Oxana [17]2 years ago
5 0

Answer:

n/4 + 5 = 9

n = 16

Quotient means division so number divided by 4, then you add five

and it would equal 9.

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Determine the indicated side length of the golden rectangle. round your answer to the nearest hundreth....
docker41 [41]
I think its d. Because it is to the nearest thousands. And you cannot find the long sides of the rectangle,because you need another one info. about the number of the long sides or the perimeter or the area. Im happy if i helped you
4 0
3 years ago
Find the mean, meadian, mode and range for each set of data 6, 9, 2, 4, 3, 6, 5
Helga [31]

Mean: Add up the numbers and divide the sum by the number of values in the set.

6 + 9 + 2 + 4 + 3 + 6 + 5 = 35

35 / 7 = 5

Median: Sort the set from the smallest value to the largest value and select the number in the middle. If the count of the set if even, then select the two middle values and take their mean average.

2, 3, 4, 5, 6, 6, 9

            ^

So, the median average is 5.

Mode: What number appears the most frequently?

The mode of the set is 6 because it appears twice.

Range: Sort the set by ascending order and take the smallest value and subtract that from the largest value in the set.

9 - 2 = 7

The range is 7.

6 0
2 years ago
Read 2 more answers
Find the slope of the line that passes through the points (1,-4) and (3,-1).
sveta [45]

Answer: E

Step-by-step explanation: I used m.athway

8 0
3 years ago
Find the x-intercepts of the parabola with vertex (1,-108) and y-intercept (0,-105). Write your answer in this form: (X1,y1), (x
Stolb23 [73]

Answer:

(7, 0) and (-5, 0)

Step-by-step explanation:

<u>Vertex form</u>

y=a(x-h)^2+k  

(where (h, k) is the vertex)

Given:

  • vertex = (1, -108)

\implies y=a(x-1)^2-108

Given:

  • y-intercept = (0, -105)

\implies a(0-1)^2-108=-105

\implies a(-1)^2=-105+108

\implies a=3

Therefore:

\implies y=3(x-1)^2-108

The x-intercepts are when y = 0

\implies 3(x-1)^2-108=0

\implies 3(x-1)^2=108

\implies (x-1)^2=36

\implies x-1=\pm \sqrt{36}

\implies x=1\pm 6

\implies x=7, x=-5

Therefore, the x-intercepts are (7, 0) and (-5, 0)

7 0
2 years ago
Anyone help please....
MissTica

mean= 4.1

median= 1,2,3,4,5,6

mode= 6

Step-by-step explanation:

4 0
3 years ago
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