There are, 3 x 2 x 1 = 6 possible ways of arranging the three digits. Therefore in that set of 720 possibilities, each unique combination of three digits is represented 6 times. So there are 720 possible combinations.
If the position at time <em>t</em> is
<em>s(t)</em> = (1 m/s³) <em>t</em> ³
then the average velocity over <em>t</em> = 2 s and <em>t</em> = 2.001 s is
<em>v</em> (ave) = (<em>s</em> (2.001 s) - <em>s</em> (2 s)) / (2.001 s - 2 s)
<em>v</em> (ave) = ((1 m/s³) (2.001 s)³ - (1 m/s³) (2 s)³) / (2.001 s - 2 s)
<em>v</em> (ave) ≈ (8.01201 m - 8 m) / (0.001 s)
<em>v</em> (ave) ≈ 12.006 m/s
The locomotive is 40 ft long.
40 ft = 40 * 12 in. = 480 in.
The locomotive is 480 inches line.
The model is 16 inches long.
480/16 = 30
The real locomotive is 30 times longer than the model.
A window on the locomotive is 30 times wider than a window on the model.
Answer:
nx^(n-1).
Step-by-step explanation:
d/dx (x^n)
We multiply by n than subtract 1 from the exponent (n):
= n x^(n-1)
Numerical examples:
d(x^3) dx = 3 * x^(3-1)
= 3x^2.
d(2x^5)/dx = 5*2 x^(5-1)
= 10x^4.
