Answer:
word = input('Enter a single word: ', 's');
n = length(word);
nodupWord = [];
for i = 1:n
dup = false;
c = word(i);
for j = 1:i-1
if word(j) == c
dup = true;
break;
end
end
if ~dup
nodupWord = [nodupWord, c]; %add the non-duplicate char to end
end
end
disp(['Adjusted word: ', nodupWord])
Explanation:
The code is in Python.
No speak a Spanish ............
The nursing usually takes up to 18 months, i.e. one year and a half.
The baby dolphin may however remain with his mum for up to 3-6 years.
Answer:
Print Layout, Full-Screen Reading, Web Layout, Outline, and Draft are 5 different views in Word.
Hope this helps!
Answer:
Option (4) is the correct answer.
Explanation:
In Java programming language ,array collection starts from 0 index location and ends in a size-1 index location. So to access the last elements the user needs to use a[Size-1] statement. so to modify the value of the last location of the array the user needs to use "a[size-1]= element;".
But when the user wants to add some new value to the end of the array list collection then he needs to use the statement--
a.add(element); //where add is a function, element is a value and a is a array list object.
Another option is invalid because--
- Option 1 is not the correct because "a[3]=element;" modify the value of the 3rd element of the array.
- Option 2 gives a compile-time error because add functions bracts are not closed.
- Option 3 gives the error because a[4] gives the location of the 5th element of the array but the above question says that a is defined with 4 elements.
