Answer:
#include <iostream> // header file
using namespace std; // namespace
int main ()
{
int n, x1, i=0,odd_Sum = 0, even_Sum = 0; // variable declaration
cout << "Enter the number of terms you want: ";
cin >> n; // user input the terms
cout << "Enter your values:" << endl;
while (i<n) // iterating over the loop
{
cin >> x1; // input the value
if(x1 % 2 == 0) // check if number is even
{
even_Sum = even_Sum+x1; // calculate sum of even number
}
else
{
odd_Sum += x1;
// calculate sum of odd number.
}
i++;
}
cout << "Sum of Even Numbers is: " << even_Sum << endl; // display the sum of even number
cout << "Sum of Odd Numbers is: " << odd_Sum << endl; // display the sum of odd number
return 0;
}
Output:
Enter the number of terms you want:3
Enter your values:2
1
78
Sum of Even Numbers is:80
Sum of Odd Numbers is:1
Explanation:
In this program we enter the number of terms by user .After that iterating over the loop less then the number of terms .
Taking input from user in loop and check the condition of even. If condition is true then adding the sum of even number otherwise adding the sum of odd number.
Finally print the the sum of the even number and odd integers.
