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Schach [20]
3 years ago
9

Find the basic period and basic frequency of the function g(t)=8cos(10πt)+sin(15πt)

Computers and Technology
1 answer:
Lady_Fox [76]3 years ago
5 0

Answer:

The period is

\frac{2\pi}{5}

The frequency is

\frac{5}{2\pi}

Explanation:

The period of both functions will be LCM of both period.

The period of cos is

\frac{\pi}{5}

The period of sin is

\frac{2\pi}{15}

Let convert each into degrees.

\frac{\pi}{5}  = 36

\frac{2\pi}{15}  = 24

Find the least common multiple between 36 and 24, which is 72.

Convert 72 into radians

72 =  \frac{2\pi}{5}

The period is 2pi/5.

The frequency is equal to

1/period.

so the frequency is

\frac{1}{ \frac{2\pi}{5} }  =  \frac{5}{2\pi}

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Consider the following recursive method: public int someFun(int n) { if (n <= 0) return 2; else return someFun(n-1) * someFun
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Answer:

(a) someFunc(3) will be called 4 times.

(b) For non negative number n someFunc method calculates 2^2^n.

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So now we have two someFunc(4) now each someFunc(4) will call someFunc(3) two times.Hence the call to someFun(3) is 4 times.

someFunc(n) calculates someFunc(n-1) two times and calculates it's product.

someFunc(n) = someFunc(n-1)^2..........(1)

someFunc(n-1)=someFunc(n-2)^2..........(2)

substituting the value form eq2 to eq 1.

someFunc(n)=someFunc(n-2)^2^2

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= someFunc(n-n)^2^n.

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3 years ago
Which item is used for formatting in responsive web design?
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3) Improving image quality

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