24+20=44
4(6+5)=44
the first one
Ok
y=-0.04x^2+8.3x+4.3
when the rocket reaches the ground (when height=0, ie when y=0), then the rocket will land, find the x coordinate
set y=0
0=-0.04x^2+8.3x+4.3
use quadratic formula
if you have ax^2+bx+c=0, then
x=

a=-0.04
b=8.3
c=4.3
x=

x=208.017 or -0.516785
xrepresents horizontal distance
you cannot have a negative horizontal distance unless you fired and theh wind blew it backwards
therefor x=280.017 is the answer
208.02 m
Answer:
Step-by-step explanation:
4x+2y = -24 -------------(i)
<u> -4x+y = 12 -</u>------------(ii)
add (i) &(ii) 3y = -12
y = -12/3
y = -4
Put y = (-4) in (i)
4x + 2*(-4) = -24
4x - 8 = -24
4x = -24 + 8
4x = -16
x = -16/4
x = -4
Answer:
y = 4
Step-by-step explanation:
Step 1: Write equation
9/4y - 12 = 1/4y - 4
Step 2: Solve for <em>y</em>
- Subtract 1/4y on both sides: 8/4y - 12 = -4
- Simplify: 2y - 12 = -4
- Add 12 to both sides: 2y = 8
- Divide both sides by 2: y = 4
Step 3: Check
<em>Plug in x to verify it's a solution.</em>
9/4(4) - 12 = 1/4(4) - 4
9 - 12 = 1 - 4
-3 = -3