Express 192 as a prime factors in order
1 answer:
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Answer:
see below
Step-by-step explanation:
some of your answers that you currently have are wrong, I'll note those mistakes below
- when factoring (ie 5x+15) only factor out things that can divide both numbers into a whole number ratio
5x+15 = 5(x+3), not (x+3)(x+5)
ie
we see that 10x can divide the numerator in a whole number ratio
= 10x(x+2), not (x+2)(x+10)
second mistake: the first binomial expansion is incorrect.
you have the expansion formula right, but you added terms wrong, go look at it again
3. x^2+3x+2/ x^2+5x+6
(x+1)(x+2)/(x+3)(x+2)
(x+1)/(x+3)
4. (x^2+6x+8)/(x^2-16)
(x+4)(x+2)/(x+4)(x-4)
(x+2)/(x-4)
5. we can't simplify that any more, x and y are different variables so therefore we cannot cross out stuff on numerator and denominator
6. (x^4y^6)^2
(x^4y^6)(x^4y^6) =
remember that (x^a)(x^b) = x^(a+b)
or remember that (x^a)^b = x^ab