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irga5000 [103]
3 years ago
9

What is the Pythagorean Theorem used for? *

Mathematics
2 answers:
Alexandra [31]3 years ago
4 0
B. to find the length of a missing side of a right triangle
Dovator [93]3 years ago
3 0

Answer:

B

Step-by-step explanation:

In  a right  triangle is used the theorem  so

If  <A=90  grades

BC^2=AB^2+AC^2

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Calculate the distance between points (0,0) and (4, 6) on the coordinate plane.​
abruzzese [7]
4 up and 6 right


i hope this helped
5 0
3 years ago
The cost of 7 scarves is $43.75. What is the unit price?
Lisa [10]
The unit price is $6.25 because $43.75 divided by 7 is $6.25
5 0
3 years ago
Read 2 more answers
Which of the following is a quadratic function in standard form?
Veseljchak [2.6K]

Answer:

A.

Step-by-step explanation:

Standard form is as follows...

AX^2 + BX + C

- Hope that helped! Please let me know if you need further explanation.

6 0
4 years ago
Read 2 more answers
To make the chocolate shake, Dona added 40 mL of chocolate syrup,
Vsevolod [243]

Answer:

0.225 L of milk, would be required if she uses 450 m L of water.

Step-by-step explanation:

Here, to make the shake, ingredients used by Dina are:

40 m L of chocolate syrup,

200 m L of milk, and 400 m L of water.

So, here Amount of water used = 2 x ( Amount of Milk used)  .......  (1)

Now,again the amount of water used by Dona = 450 m L

Let us assume the milk used by her  = k m L

⇒ 450 m L = 2 x ( k m L)     ( from (1))

or, 450 = 2  k

⇒  k    = 450/2  = 225

⇒   k   = 225 m L

Also, 1 m L = 0.001 L

So, 225 m L = 225 x  0.001  = 0.225 L

⇒   k   = 0.225  L

Hence, 0.225 L of milk, would be required if she uses 450 m L of water.

5 0
4 years ago
Will Mark Brainlest helpppp​
Anvisha [2.4K]

Answer:

R = \left[\begin{array}{ccc}-3&-2\\1&-3\\\end{array}\right]

Step-by-step explanation:

P - Q + R = I ( I is the identity matrix )

\left[\begin{array}{ccc}2&4\\3&5\\\end{array}\right] - \left[\begin{array}{ccc}-2&2\\4&1\\\end{array}\right] + R = \left[\begin{array}{ccc}1&0\\0&1\\\end{array}\right] ( subtract corresponding elements )

\left[\begin{array}{ccc}2-(-2)&4-2\\3-4&5-1\\\end{array}\right] + R = \left[\begin{array}{ccc}1&0\\0&1\\\end{array}\right]

\left[\begin{array}{ccc}4&2\\-1&4\\\end{array}\right] + R = \left[\begin{array}{ccc}1&0\\0&1\\\end{array}\right]

R = \left[\begin{array}{ccc}1&0\\0&1\\\end{array}\right] - \left[\begin{array}{ccc}4&2\\-1&4\\\end{array}\right] = \left[\begin{array}{ccc}-3&-2\\1&-3\\\end{array}\right]

6 0
3 years ago
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