The standard deviation of a point estimator is the <u>standard error.</u>
"The point estimate is used to estimate the exact value of any parameter. For example, an internet poll says that 45% of Americans are concerned for the environment."
"Point estimates is a good measure but the problem with this parameter is that the sample of the statistics may vary so that there is a chance of sampling error."
"As the researcher is unable to presume that closeness of the sample statistics parameter with respect to the parameter so researcher refers to calculate the standard error instead of point estimate."
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Answer:
25
Step-by-step explanation:
Given the model:
y=−3.5x+400
Number of children in amusement park = y
Temperature = x
On a certain day:
Temperature = 90°F
Number of children in park = 60
Using the model :
The predicted number of children in park when temperature is 90°F would be :
y = - 3.5(90) + 400
y = - 315 + 400
y = 85
Model prediction = 85 children
Actual figure = 60
Residual :
|Actual - predicted | = |60 - 85| = 25 children
It's 28 pounds. 3,500/125 = 28 pounds.
In order to find height from where ball is dropped, you have to find height or h(t) when time or t is zero.So plug in t=0 into your quadratic equation:h(0) = -16.1(0^2) + 150h(0) = 0 +150h(0) = 150 ft is the height from where ball is dropped. When ball hits the ground, the height is zero. So plug in h(t) = 0 and solve for t.0 = -16.1t^2 + 15016.1 t^2 = 150t^2 = 150/16.1t = sqrt(150/16.1)t = ± 3.05Since time cannot be negative, your answer is positive solution i.e. t = 3.05
It might be A
Example: I tried to do the math and i came out with 1/20 so try it. i’m very sorry if it’s wrong