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lesantik [10]
3 years ago
15

Factor n(2n+3)+4(2n-3)

Mathematics
1 answer:
zavuch27 [327]3 years ago
3 0
The answer would be 2n^2+3n+ 8n-1
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Write the following number in standard form. three and fifteen hundredths 3.15 3.015 315 3.105
soldier1979 [14.2K]
3.105 I believe.. not 100% sure.
3 0
3 years ago
Jose is going to invest in an account paying an interest rate of 6.1% compounded continuously. How much would Jose need to inves
VikaD [51]

Answer:

P≈ 87784.11

Step-by-step explanation:

i don't know,  I saw the solution on Delta Math

​

8 0
3 years ago
The hire purchase price of a fridge is 16400. 25% is paid as deposit, the rest is spread over 12 equally monthly instalments. If
Flauer [41]

Answer: a. 13120

b. 4100

c. 1025

d. 3280

Step-by-step explanation:

(a) find the costs price of the fridge

Since the cash price is 20% less the hire purchase price, then the cost of the fridge will be:

= (100% - 20%) × 16400

= 80% × 16400

= 0.8 × 16400

= 13120

(b) calculate the deposit

Since 25% is paid as deposit, the deposit will be:

= 25% × 16400

= 0.25 × 16400

= 4100

(c) what is the monthly installments

Monthly installments will be:

= (16400 - 4100)/12

= 12300/12

= 1025

(d) what is the differences between the cash price and the hire purchase price.

This will be:

Hire purchase price = 16400

Cash price = 13120

= 16400 - 13120

= 3280

3 0
3 years ago
What’s the answer to this
Alchen [17]

Answer:

C

Step-by-step explanation:

y=1/x, the reciprocal is the same. Reciprocal would be reflected across y=x

6 0
3 years ago
A submarine dives at a constant speed of 10 m/s at a diving angle measured from the vertical
valina [46]

Answer:

155.3 m

Step-by-step explanation:

<u>We have:</u>

θ: is the angle measured from the vertical = 75 °

v = is the speed of the submarine = 10 m/s

t = 1 min

The deep of the front end of the submarine at the end of a 1-minute drive is given by the following ratio:

cos (\theta) = \frac{x}{d}  

<u>Where:</u>

d: is the distance traveled by the submarine in 1 minute

x: is the deep to find

The distance, d, is:

d = v*t = 10 \frac{m}{s}* 1 min * \frac{60 s}{1 min} = 600 m

Now, the deep is:

cos (75) = \frac{x}{600}  

x = cos(75)*600 = 155.3 m

Therefore, the deep of the front end of the submarine at the end of a 1-minute drive is 155.3 m.

I hope it helps you!

3 0
3 years ago
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