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Maksim231197 [3]
4 years ago
5

Write a Python program that can convert an integer between 0 and 15 into hexnumber (including 0 and 15). The user enters an inte

ger from the console,and the program displays the corresponding hex number. If the user enters an integer out of range, the program displays a warning message about the invalid input.
Computers and Technology
1 answer:
Mamont248 [21]4 years ago
8 0

Answer:

number = int(input("Enter an integer: "))

if 0 <= number <= 15:

   print(str(number) + " in hexadecimal is: " + str(hex(number)))

else:

   print("Invalid input!")

Explanation:

Ask the user to enter an integer and set it to the number

Check if the number is between 0 and 15. If it is, then convert the number into hexadecimal number using hex method and print it. Otherwise, print a warning message.

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The missing segment of the code illustrates the use of functions.

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The code segment that complete the code in the question is as follows:

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<em />

<em />

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<em>def calc_pyramid_volume(length, width, height): </em>

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<em>length = float(input()) </em>

<em>width = float(input()) </em>

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<em />

See attachment for the sample run

Read more about functions at:

brainly.com/question/17225124

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