Answer: 37.69911 in. (Round if necessary)
Steps:
2πr
2·π·6 = 37.69911
$45,000*.10= $4500
-$4500
—————
$40500 * .10 = $4050
+4050
—————
$44550 is your answer
7e -4= 2e +13
5e=17
E=17/5 or 3.4
For a better understanding of the explanation provided here kindly go through the file attached.
Since, the weight attached is already at the lowest point at time, t=0, therefore, the equation will have a -9 as it's "amplitude" and it will be a Cosine function. This is because in cosine function, the function has the value of the amplitude at t=0.
Now, we know that the total angle in radians covered by a cosine in a given period is
and the period given in the question is t=3 seconds. Therefore, the angular velocity,
of the mentioned system will be:

Combining all the above information, we see that the equation which models the distance, d, of the weight from its equilibrium after t seconds will be:

Thus, Option B is the correct option. The attached diagram is the graph of the option B and we can see clearly that at t=3, the weight indeed returns to it's original position.
I believe the answer is D