First term is found by putting n = 1:
4(1)+3 = 7
Next term = 4(2)+3 = 11
First 5 terms are 7, 11, 15 , 19
Answer:
Hello a value is missing in your question below is the value
samples of n = 10
answer : 24.63 < μ < 25.370
Step-by-step explanation:
Given :
Sample size = n = 10
Z∝/2 = Z0.0256 = 1.95
next calculate for margin of error
E = Z∝/2 * ( 0.6 / / )
= 0.370
therefore at 94.87% confidence interval the estimated population mean is
x - 0.370 < μ < x + 0.370
25 - 0.370 < μ < 25 + 0.370
24.63 < μ < 25.370
The Answer is D. It is the x-values.
Answer:
The liters that the tank will contain at 5:11 PM that day are:
Step-by-step explanation:
Firstly, you must identify the outlet flow of the water pumped from the tank, for this, you must subtract the last volume given from the first volume:
- 19,140 L - 8,097 L = 11,043 L
And the minutes that passed from the first volume until the last volume given (18 minutes from 4:47 PM to 5:05 PM), so, you must divide that two values to obtain the outlet flow:
- Outlet flow =
- Outlet flow =
- Outlet flow = 613.5
Now, you must see the next hour given (5:11 PM), if you see, from 5:05 PM to 5:11 PM has passed 6 minutes, taking into account this, you replace the equation of outlet flow to clear the volume:
- Outlet flow =
- Volume = Outlet flow * time
And replace the values to obtain the new volume pumped:
- Volume = 613.5 * 6 min
- Volume = 3681 L.
At last, you must subtract these liters from the last volume identified in the tank:
- New Volume in the tank = 8097 L - 3681 L
- New Volume in the tank = 4416 L
The volume in the tank at 5:11 PM is <u>4416 Liters</u>.
Answer:
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