A retail outlet's sales for January were $45,000. In February, these sales decreased 10%; but from February to March, sales incr
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The height of the cone is 4 cm (approx).
Step-by-step explanation:
Given,
The radius (r) of the cone = 4.96 cm
Volume (V) = 102 cm³
To find the height (h) of the cone.
Formula
The volume of a cone V = πr²h
Now,
According to the problem,
πr²h = 102
or, ×
×(4.96)²h= 102
or, h =
or, h = 3.95 = 4 (approx)
so,
Height = 4 cm (approx)
Take the derivitive
f'(x)=3x^2+12x
find where it equals zero
it equal zero at x=0 and x=-4
find the y values
f(0)=-36
f(-4)=-4
the critical points are (0,-36) and (-4,-4)
make sign chart
evalutat f'(x) at x=-5 and x=-1 and x=1, and see their signs
f'(-5)=(+)
f'(-1)=(-)
f'(1)=(+)
see below attachment
max is where sign changes from (+) to (-)
min is where sign changes from (-) to (+)
so
max at (-4,-4)
min at (0,-36)
none of the options are correct, do you have te right problem?
f'(x)=3x^2+12x
find where it equals zero
it equal zero at x=0 and x=-4
find the y values
f(0)=-36
f(-4)=-4
the critical points are (0,-36) and (-4,-4)
make sign chart
evalutat f'(x) at x=-5 and x=-1 and x=1, and see their signs
f'(-5)=(+)
f'(-1)=(-)
f'(1)=(+)
see below attachment
max is where sign changes from (+) to (-)
min is where sign changes from (-) to (+)
so
max at (-4,-4)
min at (0,-36)
none of the options are correct, do you have te right problem?