Answer:
Step-by-step explanation:
\[2~ sin^2 x+3sin x+1=0\]
\[2sin^2x+2sin x+sin x+1=0\]
2sinx(sin x+1)+1(sin x+1)=0
(sin x+1)(2 sin x+1)=0
either sin x+1=0
sin x=-1=sin 3π/2=sin (2nπ+3π/2)
x=2nπ+3π/2,where n is an integer.
or 2sin x+1=0
sin x=-1/2=-sin π/6=sin (π+π/6),sin (2π-π/6)=sin (2nπ+7π/6),sin (2nπ+11π/6)
x=2nπ+7π/6,2nπ+11π/6,
where n is an integer.
Answer:
Step-by-step explanation:
if m and n are irrational number then the product of mn sometimes rational and sometime irrational
ex: √5 *√2=√10 irrational
ex: √8*√2=√16=4 rational
b-y=|x|+3
explain why |x|+3≥|x+3|
absolute value of any number is always positive
x |x|+3 ≥ |x+3|
1 4 = 4 in this case equal
2 5 5
-2 5 ≥ 1 in this case |x|+3≥|x+3|
in case of negative value of x then |x|+3>|x+3|
Answer:
y=10x+3
Step-by-step explanation:
you can't solve this because there is only one equation, so i guess you want it in slop-intercept form
-3^2= -(3)^2
The exponent of 2 only applies to the number 3. -(3)^2 should equal -9. This is true because according to the order of operations, exponents should be evaluated before multiplication. The negative sign here represents -1* 3^2.
If you want to find -3 to the power of 2 it must be written (-3)^2.