Question is Incomplete, Complete question is given below.
Prove that a triangle with the sides (a − 1) cm, 2√a cm and (a + 1) cm is a right angled triangle.
Answer:
∆ABC is right angled triangle with right angle at B.
Step-by-step explanation:
Given : Triangle having sides (a - 1) cm, 2√a and (a + 1) cm.
We need to prove that triangle is the right angled triangle.
Let the triangle be denoted by Δ ABC with side as;
AB = (a - 1) cm
BC = (2√ a) cm
CA = (a + 1) cm
Hence,
Now We know that
So;
Now;
Also;
Now We know that
[By Pythagoras theorem]
Hence,
Now In right angled triangle the sum of square of two sides of triangle is equal to square of the third side.
This proves that ∆ABC is right angled triangle with right angle at B.
Answer:
8.9k
Step-by-step explanation:
We just have to add together the length of the three sides to find the perimeter of the triangle.
(1.8k-5)+(3.5+6.1k)+(k+1.5) = 1.8k-5+3.5+6.1k+k+1.5
Combine like terms.
1.8k<em>-5+3.5</em>+6.1k+k<em>+1.5</em> = 8.9k <em>+ 0 </em>
= 8.9k
Answer:
Step-by-step explanation:
-3/-5 is greater because -3/-5 = 3/5
So, -3/-5 is greater
X - (-150) = 200
x + 150 = 200
x + 150 (-150) = 200 (-150)
x = 200 - 150
x = 50
hope this helps
Answer:
3
Step-by-step explanation:
- 4x + 1 = - 11
- 4x = - 11 - 1
- 4x = - 12
x = - 12 / - 4
x = 3