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Andrej [43]
3 years ago
6

A 50-foot ladder leans against a wall, as shown in the figure below. If the base of the ladder is 30 feet away from the wall, ho

w tall is the wall?
Mathematics
1 answer:
notka56 [123]3 years ago
4 0

50^2 + 30^2 = x^2

2500 + 900 = x^2

3400 = x^2

x = sqrt(3400)

x = 58.31

 height is 58.31 feet ( round answer as needed)

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Olegator [25]

Answer:

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Step-by-step explanation:

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3 years ago
If a rectangle measures 21 centimeters by 28 centimeters what is the length in centimeters of the diagonal of the rectangle
SOVA2 [1]

Answer:

35cm

Step-by-step explanation:

Given data

Length= 21cm

Width= 28cm

Diagonal= ???

Applying Pythagoras theorem

D^2= L^2+W^2

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3 years ago
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Lena [83]

Answer:

D. 127.5 square units

Step-by-step explanation:

AC=17

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Diagonal (1&2) are given, base of the rhombus is also given.

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Area of a rhombus=1/2×d1×d2

=1/2×17*15

=1/2×255

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