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iren2701 [21]
3 years ago
12

Students pass a test it they score 50% or more. the marks of a large number of students were sampled and the mean and standard d

eviation were calculated as 42% and 8% respectivley. assuming this data is normally distributed, what percentage of students pass the test
Mathematics
1 answer:
Schach [20]3 years ago
3 0
So we are given that the mean is 42% and the sd (standard deviation) is 8%
Assuming our data is normal we can use the 68-95-99 rule

So one thing you should realize is that 42% + 8% is 50% which is passing. That is one standard deviation higher. So we use:
 
100 - 68 - 13.5 - 2.35 - 0.15  = 16. That means 16% of students passed the test. Which is terrible. They probably need to hit the books more.

Anyways if you have any question feel free to message me!
Hopes this helps!
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Write the first five terms of the geometric sequence in which a1=64 and the common ratio is 5/4
natita [175]

Remember that finding terms in a geometric sequence is done by multiplying the previous term by a common ratio r. For example, we can say:

a_2 = a_1 r

a_3 = a_2 r = (a_1 r)r = a_1 r^2


We have a_1 = 64. To find a_2, let's multiply this term by \frac{5}{4}:

a_2 = 64 \cdot \frac{5}{4} = 80


Now, let's use this to find all of our other terms:

a_3 = 80 \cdot \frac{5}{4} = 100

a_4 = 100 \cdot \frac{5}{4} = 125

a_5 = 125 \cdot \frac{5}{4} = \frac{625}{4}


Thus, our terms are 64, 80, 100, 125, and (625/4).

8 0
3 years ago
Find the equation of the line that is perpendicular to y = two over three x and contains the point (four,-eight)
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The equation would be f(x)=-3/2x-2
Hope this helped and sorry if I am wrong!
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3 years ago
a jar contains 6 jellybeans, 4 green jellybeans, and 4 blue jelly beans. if we choose a jellybean, then another without putting
posledela
Probability first one is blue is 4/6+4+4=4/14
the second one is also blue is 4-1/6+4+4-1=3/13

The probability of getting blue both time is 4/14*3/13=12/182=0.0659=6.59%

Answer:
0.0659 or 6.59%
8 0
3 years ago
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