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3 years ago

Lunar missions have helped scientists track the motion of the moon. What have they discovered about its motion?

Mathematics

1 answer:

Vikki [24]3 years ago

4 0

Answer:

Step-by-step explanation:

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What is the domain of F(x) = 1/x ?

Elenna [48]

Step-by-step explanation:

The domain is the possible x values of a function.

Since our function is a reciprocal function, our denominator can't equal 0. Note x=0, is a vertical asymptote.

So our domain is

All Reals except 0,

or (-oo,0) U (0, oo).

6 0

2 years ago

Which of the following vectors are orthogonal to (-1,3)? Check all that apply.

Aliun [14]

First vector orthogonal<span> to ⟨−</span>3<span>,4</span>

7 0

3 years ago

Question 19 of 25

Ronch [10]

The next step in the series will be Option B

<h3>What is a Series ?</h3>

A series is the sequence of object in pattern.

From the given figure it can be seen that the red and blue colour semicircle are shifting alternately , and the number series is increasing by 1

Therefore the next step is red on the right side , blue on the left side and no. 4 written on blue

Therefore Option B is the right answer.

To know about Series

brainly.com/question/15415793

#SPJ1

4 0

2 years ago

Find the rate and unit rate:

Alenkinab [10]

A: 24 miles per 1 gallon

5 0

3 years ago

Read 2 more answers

4x2 + 4x - 1, evaluate and fully simplify each of the - For the function f(0) following f(s + h) f(x + h) - f(5) h 10

Andrew [12]

Given the function f(x);

$f(x)=-4x^2+4x-1$

Evaluating the function f(x+h);

$\begin{gathered} f(x+h)=-4(x+h)^2+4(x+h)-1 \\ f(x+h)=-4(x^2+2xh+h^2)^{}+4(x+h)-1 \\ f(x+h)=-4x^2-4h^2-8xh^{}+4x+4h-1 \end{gathered}$

So;

$f(x+h)=-4x^2-4h^2-8xh^{}+4x+4h-1$

Evaluating the second function;

$\begin{gathered} \frac{f(x+h)-f(x)}{h}=\frac{-4x^2-4h^2-8xh^{}+4x+4h-1-(-4x^2+4x-1)}{h} \\ \frac{f(x+h)-f(x)}{h}=\frac{-4x^2-4h^2-8xh^{}+4x+4h-1+4x^2-4x+1}{h} \\ \frac{f(x+h)-f(x)}{h}=\frac{-4x^2+4x^2-4h^2-8xh^{}+4x-4x+4h-1+1}{h} \\ \frac{f(x+h)-f(x)}{h}=\frac{-4h^2-8xh^{}+4h}{h} \end{gathered}$

simplifying further;

$\begin{gathered} \frac{f(x+h)-f(x)}{h}=\frac{-4h^2-8xh^{}+4h}{h}=-4h-8x+4 \\ \frac{f(x+h)-f(x)}{h}=-4h-8x+4 \end{gathered}$

Therefore, we have;

$undefined$

7 0

1 year ago