your answer is 53 1/4.
There are 7 days in a week. multiply 15 1/4 by 7. you should get 106 3/4. subtract that from 160, and you should be left with 53 1/4. I hope this helped :))
Answer:
The teams can be placed in 479,001,600 ways.
Step-by-step explanation:
To solve this question, we want to know in how many ways 12 elements can be arranged.
Number of possible arrangements of x elements:
The number of possible arrangments of x elements is given by:
In this question:
12 teams, so arrangment of 12 elements.
The teams can be placed in 479,001,600 ways.
The slope of the line MN where M (9,6) and N (1,4) can be obtained by obtaining the rate of the rise over the run. This is shown below:
(y2 - y1)/(x2 - x1) = (4 - 6)/(1 - 9) = (-2)/(-8)
m1 = 1/4
The slope of the line perpendicular to line MN can be obtained by taking the negative reciprocal of the slope of line MN.
m1 = 1/4
m2 = -1/m1 = -1/(1/4) = -4
Therefore, the slope of the line perpendicular to line MN is -4.
Answer:
Helen’s net is correct because she reorganized the solid as a triangular prism.
This is because the net has a rectangular base and 4 triangular sides.
Step-by-step explanation:
Rectangular SA one side+1 = 30 x 9 = 270 + 1s= 270 x 2 =540sq^2
Rectangular side one side +1 = 18 x 9 = 162 +1s = 162 x 2 = 324sq^2
2 x 2 triangular sides either end = 4/3 x 15 x 27.3 + 18 x 30.9 = 409.5 (x2) = 819sq^2
=864 + 360
Pyramid area = 1236.71sq^2
Volume = V=1620^3
The solution to the problem is as follows:
let y = asinx + bcosx
<span>
dy/dx = acosx - bsinx </span>
<span>
= 0 for max/min </span>
<span>
bsinx = acosx </span>
<span>
sinx/cosx = a/b </span>
<span>
tanx = a/b </span>
<span>
then the hypotenuse of the corresponding right-angled triangle is √(a^2 + b^2) </span>
<span>the max/min of y occurs when tanx = a/b </span>
<span>
then sinx = a/√(a^2 + b^2) and cosx = b/√(a^2 + b^2) </span>
<span>
y = a( a/√(a^2 + b^2)) + b( b/√(a^2 + b^2)) </span>
<span>
= (a^2 + b^2)/√(a^2 + b^2) </span>
<span>
= √(a^2 + b^2)</span>
I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!
