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ruslelena [56]
3 years ago
10

Given two points m and n on the coordinate plane, find the slope of line mn, and state the slope of the line perpendicular to li

ne mn: m(9,6) n(1,4)
Mathematics
1 answer:
ololo11 [35]3 years ago
3 0
The slope of the line MN where M (9,6) and N (1,4) can be obtained by obtaining the rate of the rise over the run. This is shown below:

(y2 - y1)/(x2 - x1) = (4 - 6)/(1 - 9) = (-2)/(-8)
m1 = 1/4

The slope of the line perpendicular to line MN can be obtained by taking the negative reciprocal of the slope of line MN.

m1 = 1/4
m2 = -1/m1 = -1/(1/4) = -4

Therefore, the slope of the line perpendicular to line MN is -4.
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Apply the markup for each item. Then, find the retail price. Round to two decimals places when necessary.
Alborosie

Answer:

$45 with 20% markup = $45 + $9 for a new total = $54

$7.60 with a 50% markup = $7.60 + $3.80 for new total = $11.40

Step-by-step explanation:


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#3 AB and AD are tangent to the circle centered at point C. Find the value of x. *
dezoksy [38]

Answer:

x=4

Step-by-step explanation:

tangent lines from the same point to a circle are congruent in length, so we can say that

5x+8 = 8x-4

5x -5x +8 = 8x - 5x -4

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8+4 = 3x -4 + 4

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The lakeside marina charges a $35 rental fee for a boat in addition to charging $15 per hour. Part D:what information does the i
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Answer: B.The cost of rental fee only

Step-by-step explanation:

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Essentially, the $35 is the fixed cost associated with the rental and the $15 is the variable cost to do so. If this were in a linear equation format it would take the form: y = 15x + 35.

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Step-by-step explanation:

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Calcula y comprueba las ecuaciones: porfavor alguienn la nesesito pliss a) 2X = 6 b) 10 + Z = 20 c) P + 9 = 11 d) 3X + 8 = + 29
Alexeev081 [22]

Answer:

<u>a) x = 3</u>

<u>b) z = 10</u>

<u>c) p = 2</u>

<u>d) x = 7</u>

<u>e) u = 1</u>

Step-by-step explanation:

a) 2x = 6

Despejamos x dividiendo por 2 a amabos lados de la eacuacion.

(2/2)x = 6/2

<u>x = 3</u>

Si remplazamos x en la ecuación original:

2(3)=6

6 = 6

Queda demostrado.

b) 10 + z = 20

Despejamos z restando 10 en amabos lados de la eacuacion.

10-10+z = 20-10

<u>z = 10</u>

Si remplazamos z en la ecuación original:

10 + 10=20

20 = 20

Queda demostrado.

c) p + 9 = 11

Despejamos p restando 9 en amabos lados de la eacuacion.

p + 9 - 9 = 11-9

<u>p = 2</u>

Si remplazamos p en la ecuación original:

2 + 9 = 11

11 = 11

Queda demostrado.

d) 3x + 8 = 29

Despejamos x restando 8 en amabos lados de la eacuacion y luego divideindo por 3 en ambos lados de la ecuación.

3x+8-8 = 29-8

3x = 21

(3/3)x = 21/3

<u>x = 7</u>

Si remplazamos x en la ecuación original:

3(7) + 8 = 29

21 + 8 = 29

29 = 29

Queda demostrado

e) 2u + 8 = 10

Despejamos u restando 8 en amabos lados de la eacuacion y luego divideindo por 2 en ambos lados de la ecuación.

2u+8-8 = 10-8

2x = 2

(2/2)x = 2/2

<u>x = 1</u>

Si remplazamos x en la ecuación original:

2(1) + 8 = 10

2 + 8 = 10

10 = 10

Queda demostrado

Espero te haya sido de ayuda!

5 0
2 years ago
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