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malfutka [58]
3 years ago
11

!! PLEASE HELP ME . [[ 99 POINTS ]] !!!

Mathematics
2 answers:
Kaylis [27]3 years ago
7 0
Lower quartile (xL): 27
Upper quartile (xU): 65

<span>Interquartile range (xU-xL): 38</span>
makvit [3.9K]3 years ago
3 0
The interquartile range of the following set of data is B. 37
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Here are five number cards . 2,5,7,8,9 . One of the cards is removed and the mean average of the remaining four number cards is
Elodia [21]

Answer:

7

Step-by-step explanation:

Given that there are 5 number cards.

They are 2,5,7,8,9

Total of all numbers in the cards = 2+5+7+8+9= 31

One card is removed say with number x.

Now sum new would be =31-x   ..  i

Average of remaining 4 cards = 6

So sum of remaining 4 cards = 6(4) = 24 ... ii

i and ii represent the sum of remaining 4 cards. Hence they should be equal

31-x =24

Subtract 31 from both sides to get

-x=-7

Or x =7


7 0
4 years ago
Fifty multiplied by the quantity twenty divided by a number n is greater than or equal to two hundred fifty
Fudgin [204]
4 is the correct answer
8 0
3 years ago
Find the zeros of the function f(x) = x2 + 5x + 6. A) y = 6 because the graph crosses the y-axis at 6. B) y = -0.25 because that
Fofino [41]

Answer:

D.)

Step-by-step explanation:

The zero's are referencing when y=0, note that when y=0 they are talking about the x-intercepts.  You can graph the function and see when the graph crosses the x-axis or solve for the x-values.  I will solve it via factoring and so:

f(x)=x^2+5x+6

Multiply the outer coefficients, in this case 1 and 6, and 1×6=6.  Now let's think about all the factors of 6 we have: 6×1 and 2×3.  Now is there a way that if we use any of these factors and add/subtract them they will return the middle term 5?  Actually we can say 6-1=5 and 2+3=5.  Let's try both.

First let's use 6 and -1 and so:

x^2+5x+6\\\\x^2+6x-x+6\\\\x(x+6)-1(x-6)

Notice how we have (x+6) and (x-6), these factors do not match so this is incorrect.

Now let's try 2 and 3 and so:

x^2+5x+6\\\\x^2+3x+2x+6\\\\x(x+3)+2(x+3)\\\\(x+2)(x+3)

Notice how the factors (x+3) matched up so this is a factor and so is (x+2), now to solve for the zero's let's make f(x)=0 and solve each factor separately:

Case 1:

f(x)=x+2\\\\0=x+2\\\\x=-2

Case 2:

f(x)=x+3\\\\0=x+3\\\\x=-3

So your zero's are when x=-2 and x=-3.

D.) x=-3 and x=-2 because the graph crosses the x-axis at -3 and -2.


~~~Brainliest Appreciated~~~

8 0
3 years ago
If m ∠ 1 = 101, what is the value of X?
tankabanditka [31]
The value of x is the value of x :)
3 0
3 years ago
Is 4.498 greater than, or less than 315.71 ??
Anna35 [415]
4.498 is less than 315.71. Imagine having 4 candies or 315 candies. 315 candies is a while lot greater than 4 candies.
8 0
3 years ago
Read 2 more answers
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