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nadya68 [22]
2 years ago
12

Katie earns 15$ each hour. Round to total time katie worked to the nearest hour and estimate her pay by using mulitplacation

Mathematics
1 answer:
Cloud [144]2 years ago
3 0

Answer:

How long did she work for though?

Step-by-step explanation:

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Trey is taking out a loan for $85000. It is a 20-year loan with an APR of 5.85% what will his monthly payment be?
ololo11 [35]

Answer:

$768.54 (Approximate)

Step-by-step explanation:

Trey is taking out a loan for $85000. It is a 20-year loan with an APR of 5.85%.

Therefore, if we consider the interest rate is simple interest, then using the simple interest formula, the sum will become after 20 years

85000(1 + \frac{5.85 \times 20}{100}) = 184450 dollars.

Therefore, the monthly payment for the loan will be \frac{184450}{20 \times 12} = 768.54 dollars. (Answer)

8 0
3 years ago
When a certain polynomial is divide by binomial x-3, the result is 4x-5+6/x-3. What is the polynomial
Dmitry_Shevchenko [17]
\frac{p(x)}{x-3} = 4x-5 + \frac{6}{x-3}

The polynomial p(x) can be found by multiplying 'x-3' to every term
p(x) = (4x-5)(x-3) + 6

Now distribute and you have your answer.
p(x) = 4x^2 -12x-5x+15 +6 \\  \\ p(x) = 4x^2 -17x+21


7 0
3 years ago
A rope is 72 feet long. What is the length of the rope in yards
Lostsunrise [7]
The answer would be 24 yards. This would be 24 because 3 feet equal one yard so 3/72 is 24 or 24•3.
6 0
4 years ago
Find p(-4) and p(2) for the function p(x)=11x^5-11x^4-5x^2+15x-8
egoroff_w [7]

hi,

you must replace x by the number between parenthese.

I show you with the first one and let you do the second one

p(x) = 11x^5 -11x^4 - 5x^2 +15x-8

p(-4)  =   11 (-4)^5 - 11 (-4)^4 -5(-4)² +15(-4) -8

p(-4) =     11  ( -1024- 256) - 5*16 -60-8

p(-4) =   11 ( -1280) -80-60-8

p(-4)   =    - 14080 - 148

p(-4) =   - 14 228

7 0
3 years ago
Two cars start out together from the same place. they travel in opposite​ directions, with one of them traveling 5 miles per hou
Mashutka [201]
<u>Annotation</u>
General formula for distance-time-velocity relationship is as following
d = v × t
The velocity of the first car will be v₁, the time is 2 hours, the distance will be d₁.
The velocity of the second car will be v₂, the time is 2 hours, the distance will be d₂.


One of them traveling 5 miles per hour faster than the others. That means the velocity of the first car is 5 miles per hour more than the velocity of the second car.
v₁ = v₂ + 5  (first equation)

The distance of the two cars after two hours will be 262 miles apart. Because they go to opposite direction, we could write it as below.
d₁ + d₂ = 262 (second equation)

Plug the d-v-t relationship to the second equation
d₁ + d₂ = 262
v₁ × t + v₂ × t = 262
v₁ × 2 + v₂ × 2 = 262
2v₁ + 2v₂ = 262

Plug the v₁ as  (v₂+5) from the first equation
2v₁ + 2v₂ = 262
2(v₂ + 5) + 2v₂ = 262
2v₂ + 10 + 2v₂ = 262
4v₂ + 10 = 262
4v₂ = 252
v₂ = 252/4
v₂ = 63
The second car is 63 mph fast.

Find the velocity of the first car, use the first equation
v₁ = v₂ + 5
v₁ = 63 + 5
v₁ = 68
The first car is 68 mph fast.

Answer
\boxed{\boxed{ v_{1}=68mph} }
\boxed{\boxed{ v_{2}=63mph} }
7 0
4 years ago
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