By applying the formula of trigonometric function the right hand side will
be equal to right hand side which is 1-
/
=cos2x.
Given: 1-/=cos2x.
Taking right hand side first which is cos2x.
We know that cos2x=
Now we will solve the left hand side of the equation give which is
1-/
=1-
/1+
[secant square x minus tangent square x is equal to 1]
By putting both values left hand side and right hand side we will find our solution which is :
1-tan^{2}x/1+tan^{2}x=1-/1+.
Hence proved
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Answer:
Step-by-step explanation:
Given
--- driver 1
-- driver 2
Required
The time they passed each other
First, we determine the function of driver 2.
We have that:
and
So, the function is:
The time they drive pass each other is calculated as:
Collect like terms
Divide through by 2t
Solve for -8t
Solve for t
X=180-2(60)
=180-120
=40
The length of the other angle is 40°.
Answer:
#1. Identity #2. 0 #3. No solution
Step-by-step explanation:
#1.
5y + 2 = (1/2)(10y+4)
5y + 2 = 5y + 2
This would be identity as the equation of the left and right are the same. This is not to be confused with no solution(explained below).
#2.
0.5b + 4 = 2(b+2)
0.5b + 4 = 2b + 4
0.5 b - 2b = 0
b = 0
#3.
-3x + 5 = -3x + 10
This equation has no solution because when you try to bring the -3x to one side, the x variable itself gets eliminated. So, how is it different from identity? Well in the first equation, it is true that when we try to bring the 5y one side it eliminates the y variable, however, that is also true for the constants(since if we try to bring the 2 to one side, it will be 2-2 which will equal 0, thus eliminating each other), but in this case, even if we remove the x, the constants will not equal 0, thus it will have no solution.
