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Vanyuwa [196]
3 years ago
6

How many numbers between 1 and 40 (inclusive) meet both of the conditions given in the statements below? Statement 1: The number

is divisible by 2. Statement 2: Every digit of the number is prime.
Mathematics
1 answer:
GaryK [48]3 years ago
6 0

Answer:

The answer to your question is three numbers

Step-by-step explanation:

Data

Numbers between 1 and 40

-Divisible by 2

-Prime numbers its digits.

Process

1.- Write all the numbers divisible by 2 between 1 and 40

    2   4   6   8   10  12  14  16  18  20  22 24  26  28  30  32  34  36  38

2.- Look for the numbers whose digits are prime numbers

    2                                                      22                           32

3.- Conclusion

three numbers 2, 22 and 32

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Please select the best answer from the choices provided<br><br> A<br> B<br> C<br> D
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ANSWER

The correct answer is D.

\sum_{n=1} ^{6} (n - 3) = ( - 2) + ( - 1) + (0) + (1) + (2) + (3) = 3

EXPLANATION

The given expression is

\sum_{n=1} ^{6} (n - 3)

The symbol means summation.

So we need to substitute

n=1,n=2,n=3,n=4,n=5, \:and\:n=6

into the formula and add all to get,

\sum_{n=1} ^{6} (n - 3) = (1 - 3) + (2 - 3) + (3- 3) + (4 - 3) + (5 - 3) + (6 - 3)

We simplify to obtain,

\sum_{n=1} ^{6} (n - 3) = ( - 2) + ( - 1) + (0) + (1) + (2) + (3) = 3

The correct answer is D
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