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Vanyuwa [196]
3 years ago
6

How many numbers between 1 and 40 (inclusive) meet both of the conditions given in the statements below? Statement 1: The number

is divisible by 2. Statement 2: Every digit of the number is prime.
Mathematics
1 answer:
GaryK [48]3 years ago
6 0

Answer:

The answer to your question is three numbers

Step-by-step explanation:

Data

Numbers between 1 and 40

-Divisible by 2

-Prime numbers its digits.

Process

1.- Write all the numbers divisible by 2 between 1 and 40

    2   4   6   8   10  12  14  16  18  20  22 24  26  28  30  32  34  36  38

2.- Look for the numbers whose digits are prime numbers

    2                                                      22                           32

3.- Conclusion

three numbers 2, 22 and 32

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<u>We are given:</u>

An even number 'n', multiplied by the next consecutive even number is 168

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From the given statement, we can say that:

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n² + 2n = 168

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We can see that we now have a quadratic equation, solving using splitting the middle term

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Here, we can divide both sides by either (n-12) OR (n+14)

Checking the result in both the cases:

(n + 14) = 0/(n-12)                     (n-12) = 0/(n+14)

n + 14 = 0                                 n - 12 = 0

n = -14                                      n = 12

Both these values are even and since we are not told if the number 'n' is positive or negative, both 12 and -14 are the possible values of n

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