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Alexeev081 [22]
3 years ago
5

Mr. Kowolski ordered 35 boxes of granola bars. Each box contained 24 granola bars.

Mathematics
1 answer:
Darya [45]3 years ago
6 0
Answer: 840

~ Hope this helps!
You might be interested in
Identify the coefficients in the expression below.<br><br> -6x+5y+4x+9
Montano1993 [528]

Answer:

3 coefficients in this expression are: -2x, 5y and 9 (natural number)

Step-by-step explanation:

-6x + 5y + 4x + 9

= -6x + 4x + 5y + 9

= -2x + 5y + 9

3 coefficients in this expression are: -2x, 5y and 9 (natural number)

Hope this help you :3

5 0
2 years ago
Read 2 more answers
If 112 people attend a concert and tickets for adults cost $2.25 while tickets for children cost $and total receipts for the con
Brut [27]

Answer:

42 child and 70 adult

Step-by-step explanation:

Let a = number of adult tickets

c = number of child tickets

a+c = 112

2.25a + 1.75c = 231

Solve the first equation for a

a = 112-c

Substitute this into the second equation

2.25(112-c) + 1.75c = 231

Distribute

252 - 2.25c +1.75c = 231

Combine like terms

252 -.5c = 231

Subtract 252 from each side

252-252 -.5c = 231-252

-.5c = -21

Divide each side by -.5

-.5c/-.5 = -21/ -.5

c = 42

Now can find a

a = 112-c

a = 112-42

a = 70

4 0
3 years ago
Read 2 more answers
How many numbers of possible live card hands (hands in five-card poker) drawn without replacement from a standard deck of 52 pla
makkiz [27]

The combination shows that the numbers of possible live card hands drawn without replacement from a standard deck of 52 playing cards is 2,598,960.

<h3>How to explain the information?</h3>

A permutation is the act of arranging the objects or numbers in order while combinations are the way of selecting the objects from a group of objects or collection such that the order of the objects does not matter.

Since the order does not matter, it means that each hand is a combination of five cards from a total of 52.

We use the formula for combinations and see that there are a total number of C( 52, 5 ) = 2,598,960 possible hands.

Learn more about permutations and combination on:

brainly.com/question/4658834

#SPJ1

3 0
2 years ago
If A( 6, -1) , B( 1,3) and C( k, 8) are three points such that AB = BC, find the value of k
Drupady [299]

Answer:

De value of k is 9

Step-by-step explanation:

6,-1

b(1,3)

(k,8)

am using bodmas

a6-1×1=6a

b1×3=3b

abc=8

6a+3b+8=17-8

=9

7 0
3 years ago
Given tan theta =9, use trigonometric identities to find the exact value of each of the following:_______
Ludmilka [50]

Answer:

(a)\ \sec^2(\theta) = 82

(b)\ \cot(\theta) = \frac{1}{9}

(c)\ \cot(\frac{\pi}{2} - \theta) = 9

(d)\ \csc^2(\theta) = \frac{82}{81}

Step-by-step explanation:

Given

\tan(\theta) = 9

Required

Solve (a) to (d)

Using tan formula, we have:

\tan(\theta) = \frac{Opposite}{Adjacent}

This gives:

\frac{Opposite}{Adjacent} = 9

Rewrite as:

\frac{Opposite}{Adjacent} = \frac{9}{1}

Using a unit ratio;

Opposite = 9; Adjacent = 1

Using Pythagoras theorem, we have:

Hypotenuse^2 = Opposite^2 + Adjacent^2

Hypotenuse^2 = 9^2 + 1^2

Hypotenuse^2 = 81 + 1

Hypotenuse^2 = 82

Take square roots of both sides

Hypotenuse =\sqrt{82}

So, we have:

Opposite = 9; Adjacent = 1

Hypotenuse =\sqrt{82}

Solving (a):

\sec^2(\theta)

This is calculated as:

\sec^2(\theta) = (\sec(\theta))^2

\sec^2(\theta) = (\frac{1}{\cos(\theta)})^2

Where:

\cos(\theta) = \frac{Adjacent}{Hypotenuse}

\cos(\theta) = \frac{1}{\sqrt{82}}

So:

\sec^2(\theta) = (\frac{1}{\cos(\theta)})^2

\sec^2(\theta) = (\frac{1}{\frac{1}{\sqrt{82}}})^2

\sec^2(\theta) = (\sqrt{82})^2

\sec^2(\theta) = 82

Solving (b):

\cot(\theta)

This is calculated as:

\cot(\theta) = \frac{1}{\tan(\theta)}

Where:

\tan(\theta) = 9 ---- given

So:

\cot(\theta) = \frac{1}{\tan(\theta)}

\cot(\theta) = \frac{1}{9}

Solving (c):

\cot(\frac{\pi}{2} - \theta)

In trigonometry:

\cot(\frac{\pi}{2} - \theta) = \tan(\theta)

Hence:

\cot(\frac{\pi}{2} - \theta) = 9

Solving (d):

\csc^2(\theta)

This is calculated as:

\csc^2(\theta) = (\csc(\theta))^2

\csc^2(\theta) = (\frac{1}{\sin(\theta)})^2

Where:

\sin(\theta) = \frac{Opposite}{Hypotenuse}

\sin(\theta) = \frac{9}{\sqrt{82}}

So:

\csc^2(\theta) = (\frac{1}{\frac{9}{\sqrt{82}}})^2

\csc^2(\theta) = (\frac{\sqrt{82}}{9})^2

\csc^2(\theta) = \frac{82}{81}

4 0
3 years ago
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